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328   Chapter 10  Shell Energy  Balances and Temperature Distributions in Solids and Laminar Flow

                          (a)  Derive  an  equation  for  the  steady-state  temperature distribution  in  the  wire,  assuming
                          that  Г depends  on z alone; that is, the radial  temperature variation  in the wire  is  neglected.
                          Further, assume uniform thermal and electrical conductivities in the wire, and a uniform heat
                          transfer  coefficient  from the wire  to the air stream.
                          (b)  Sketch the temperature profile  obtained in (a).
                          (c)  Compute the current, in amperes, required  to heat a platinum wire  to a midpoint temper-
                          ature of  50°C under the following  conditions:
                                             T  = 20°C        h = 100 Btu/hr • ft 2  • F
                                              L
                                             D = 0.127 mm     k=  40.2 Btu/hr •  ft  • F
                                                                              1
                                             L = 0.5 cm      k  = 1.00  X 10  ohm"  cm" 1
                                                                        5
                                                              e
                          Answers: (a) T -  T  = Щ-1  1 -  w o  "  v  - ^ "  j .  )  1.01 amp
                                         L                      ( b
                                           4/*/c V  coshy/W/DU
                                              e
                   10B.17.  Non-Newtonian  flow  with  forced-convection  heat  transfer. 1  For  estimating  the  effect  of
                          non-Newtonian viscosity  on heat transfer  in ducts, the power  law  model  of  Chapter 8 gives
                          velocity  profiles  that show  rather well the deviation  from  parabolic shape.
                          (a)  Rework  the problem  of  §10.8  (heat transfer  in  a  circular tube) for  the power  law  model
                          given  in Eqs. 8.3-2,3. Show that the final  temperature profile  is
                                                                                   3
                                                                                  3
                                      2(s  + 3)  (s + 3)  2    2     . +3     ( s  + >  ~  8  (ЮБ17-1)
                                                                      s
                                       (s + 1)  *  Us  + 1)  g  (s + l)(s  + 3)  g  4(s  + l)(s  + 3)(s + 5)
                          in which s  =  \/n.
                          (b)  Rework  Problem  10B.7  (heat transfer  in a plane slit) for  the power  law  model, Obtain the
                          dimensionless  temperature profile:
                                                          1     • | s + 3  (s + 2)(s  + 3)(2s  + 5) -  б]

                          Note that these results contain the Newtonian results  (s =  1) and the plug flow results  (s = oo).
                          See Problem 10D.2 for a generalization  of this approach.
                                                                 2
                   10B.18.  Reactor temperature profiles  with  axial heat flux  (Fig. 10B.18).
                          (a)  Show  that  for  a  heat source  that depends  linearly  on  the temperature, Eqs.  10.5-6 to  14
                          have the solutions  (for m +  Ф m_)
                                              m m_(exp m  — exp m_)
                                      &  = 1 + — +     +  —       exp  [(m +  4- m_)Z]       (10B.18-1)
                                                exp tn
                                                            exp m_
                                              m m+ exp tn+ -  mi  exp m
                                                         mi
                                                            -m   (exp nQ(exp
                                      0»  =
                                                   m +  exp m +  -  m_ exp m_
                                                 2   УИ
                                       ш  =
                                            ~-
                                               exp (m
                                                    +  + m_)                 (10B.18-3)
                                            + exp m  -  mi  exp m_
                                                  +
                          Here  Ш, =  ^B(l  ± Vl  -  (4N/B), in  which  В  = pv C L/K ei{tZZ . Some  profiles  calculated  from
                                                                     p
                                                                   0
                          these equations are shown in Fig. 10B.18.
                              1  R. B. Bird, Chem.-Ing. Technik, 31,569-572 (1959).
                              2
                               Taken from the corresponding results of G. Damkohler, Z. Elektrochem., 43,1-8, 9-13 (1937), and
                          J. F. Wehner and R. H. Wilhelm, Chem. Engr. Sci.  6, 89-93 (1956); 8, 309 (1958), for isothermal flow reactors
                                                              r
                          with longitudinal diffusion and first-order  reaction. Gerhard  Damkohler  (1908-1944) achieved fame for
                          his work on chemical reactions in flowing, diffusing systems; a key publication was in Der Chemie-
                          Ingenieur, Leipzig (1937), pp. 359-485. Richard  Herman Wilhelm (1909-1968), chairman of the Chemical
                          Engineering Department at Princeton University, was well known for his work on fixed-bed catalytic
                          reactors, fluidized transport, and the "parametric pumping'' separation process.
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