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330  Chapter  10  Shell Energy Balances and Temperature Distributions in Solids and Laminar Flow

                                                                                 2
                                                                               2
                           Now introduce the dimensionless quantities £ =  r/R  and  В = k R E /k LT 0  and show that Eq.
                                                                                   0
                                                                             e0
                           10C.1-3 then becomes
                                                            ( )       Вг-                     П0С.1-4)
                                                                        k e0
                           When the power series expressions for the conductivities are inserted into this equation we get

                                                                                    2
                                       - т 4  ( d  -  a,® -  a ® 2  + • • • ) £ ? ! )  =  B(l  -  0,0  -  )3 20  +  • • •)  (10C.1-5)
                                                       2
                           This is the equation that is to be solved for the dimensionless temperature  distribution.
                           (b)  Begin by noting that  if all the a, and  /3, were zero  (that  is, both  conductivities  constant),
                           then Eq. IOC. 1-5 would  simplify  to




                           When this is solved with the boundary conditions that 0  =  finite at f  =  0, and  0  =  0 at £ =  1,
                           we get
                                                           0  = \B(\  -  f)                    (10C.1-7)
                           This is Eq. 10.2-13 in dimensionless notation.
                               Note that  Eq. 10C-5 will have the solution  in Eq. 10C.1-7 for  small values  of  B—that  is,
                           for weak heat sources. For stronger  heat sources, postulate  that the temperature  distribution
                           can be expressed as a power series in the dimensionless heat source strength B:
                                                           2
                                                                       2
                                                  0  = \B(1 -f )(l  +  B® } + B 0 2 +  • • •)  (10C.1-8)
                           Here the 0„ are functions  of f but not  of B. Substitute  Eq. IOC. 1-8 into Eq. IOC. 1-5, and  equate
                           the coefficients  of like powers  of В to get a set of ordinary differential equations for the 0,,, with
                            n = 1,2,3,  These may be solved with the boundary conditions that 0,, = finite at f  = 0 and
                            0  = 0 at £ =  1. In this way obtain
                             И
                                                     2
                                                                                     2
                                                                              2
                                          0  = \B{\  -  £ )[l +  5 ( ^ ( 1  -  ?)  -  TsfaO ~  f ))  +  O(B )]  (lOC.1-9)
                                                              2
                                    2
                            where O(B ) means "terms of the order  of B  and  higher/'
                            (c)  For materials that are described by the Wiedemann-Franz-Lorenz  law (see §9.5), the ratio
                            k/k eT  is a constant (independent  of temperature). Hence


                            Combine this with Eqs. lOC.1-1 and 2 to get
                                           1  -  ttl® -  a 2 0  2  + • • • =  (1 -  fa® -  p 2® 2  + • • -)(1 + 0)  (lOC.1-11)
                            Equate coefficients  of equal powers  of the dimensionless temperature  to get relations among
                            the a, and the Д: a  = y8  = 1, a  = /3  + j8 , and so on. Use these relations to get
                                          x   T     2    }  2
                                                                              2
                                                     2
                                                                                     2
                                           0  = \B(\ -  f )[l  -  ^8(03,  + 2) + {(fa -  2)f )  + O(B )]  (10СЛ-12)
                     10C.2.  Viscous  heating with temperature-dependent viscosity  and thermal conductivity (Figs. 9.4-
                            1 and 2). Consider the flow  situation shown in Fig. 10.4-2. Both the stationary surface and the
                            moving  surface are maintained  at a constant  temperature  T . The temperature dependences
                                                                            o
                            of к and /x are given by
                                                        j-  = 1 + a^® + a ® 2  + •  •  •        (10C.2-1)
                                                                      2
                                                                        2
                                                    ^  = ^  = 1 + 0,6  + /3 0  + •  •  •        (10C.2-2)
                                                                       2
                            in  which the a, and Д  are constants, <p  =  \/1± is  the fluidity,  and the subscript  "0" means
                            "evaluated at T = T ." The dimensionless temperature is defined as 0  = (T -  T )/T .
                                            o                                             0   Q
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