Page 409 - Bird R.B. Transport phenomena
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§12.4  Boundary  Layer Theory  for Nonisothermal Flow  391

       EXAMPLE   12.4-2    In the preceding example  we used  the von  Karman boundary  layer  integral expressions.  Now
                           we  repeat  the same  problem but  obtain an  exact  solution  of  the boundary  layer  equations in
      Heat  Transfer  in   the limit that the Prandtl number is large—that  is, for  liquids  (see §9.1). In this limit, the outer
      Laminar Forced       edge  of the thermal boundary  layer  is well inside the velocity  boundary  layer. Therefore  it can
      Convection  along  a  safely be assumed  that v  varies  linearly with у throughout the entire thermal boundary  layer.
      Heated  Flat  Plate                     x
      (Asymptotic  Solution  SOLUTION
      for  Large  Prandtl  By combining the boundary layer equations of continuity and energy  (Eqs. 12.4-1 and 3) we  get
      Numbers) 5
                                                     ЛТ   (  С У r)V  \  AT  rf-T
                                                                xj..\*L
                                                   v V  di  ,  /  I  au dx  =  a ±_L           (12.4-18)
                           in which a  = k/pC . The leading  term of a Taylor  expansion  for  the velocity  distribution near
                                           p
                           the wall is
                                                                                               (12.4-19)

                           in which the constant с = 0.4696/V2  = 0.332 can be inferred  from  Eq. 4.4-30.
                               Substitution of this velocity  expression  into Eq. 12.4-18 gives

                                                                                               (12.4-20)

                           This has to be solved  with  the boundary conditions that Г = T  at у  = 0, and T = T x  at x  = 0.
                                                                             o
                               This equation can be solved  by  the method of combination of variables.  The choice of the
                           dimensionless  variables
                                                                        cvj /2
                                               IKTJ)  =      and  г) =     2                (12.4-21,22)
                                                                      Vl  W /
                           makes  it possible  to rewrite  Eq. 12.4-20  (see Eq. C.l-9)  as

                                                                                               (12.4-23)

                           Integration  of  this equation with  the boundary  conditions that П = 0 at r\ = 0 and П —»1  as
                           V ~^ °°  gives
                                                         exp(-rj )drj   exp(-rj )drj
                                                              3
                                                                              3
                                                      Jo             Jo                        (12.4-24)
                                                         exp(-7/  :       Г©
                           for  the dimensionless  temperature distribution. See §C4  for  a discussion  of the gamma  func-
                           tion T(n).
                               For the rate of heat loss from both sides  of a heated plate of width  W and length  L, we  get

                                          Q = 2l  J   q^dxdz


                                            = 2W\    -fcV-

                                                                                     dx
                                            =  (2WL)(T
                                                     0                               xn
                                                                                    x
                                                                                               (12.4-25)

                           which  is  the same result  as  that in Eq. 12.4-17  aside  from  a numerical constant. The quantity
                           within brackets equals  0.677, the asymptotic value  that appears in Table 12.4-1.
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