Page 498 - Bird R.B. Transport phenomena
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478  Chapter 15  Macroscopic Balances for Nonisothermal Systems

                     15B.3.  Steady flow  of  ideal gases in ducts of constant cross section.
                            (a)  Show  that, for  the horizontal flow  of  any  fluid  in a circular duct  of  uniform  diameter D,
                           the rf-form of the mechanical energy  balance, Eq. 15.4-1, may be written as

                                                       vdv  + ^dp  + \v4e v  = О               (15В.З-1)

                            in which de v  = (4f/D)dL  Assume flat  velocity  profiles.
                            (b)  Show that Eq. 15B.3-1 may be rewritten as

                                                   v dv  + d( ^ ) + [ — )dp + \v4e v  = О      (15В.З-2)
                                                          v  /  \p /
                            Show  further  that, when use  is made  of  the d-form  of  the mass  balance, Eq. 15B.3-2  becomes
                            for  isothermal flow of an ideal  gas

                                                         ,   2RT dv   ~ dv                     ,- „  о оч
                                                             ~W^~ ^                            (15B.3-3)
                                                         d6v  =     2
                            (c)  Integrate Eq.  15B.3-3 between  any  two  pipe  cross  sections  1 and  2 enclosing  a total pipe
                            length  L. Make use  of  the ideal  gas  equation  of  state  and  the macroscopic mass  balance  to
                            show  that v /v-  ~ р /р 2  = Р\1ръ so that the "mass  velocity"  G can be put in the form
                                           л
                                        [
                                     1
                                                    /PiPid  -  r)
                                         G  = p v  =   —:        {isothermal flow of ideal gases)  (15B.3-4)
                                              x x
                                             2
                            in  which  r  =  ip /p\) .  Show  that,  for  any  given  value  of  e  and  conditions  at  section  1,
                                         2                                   v
                            the  quantity  G reaches  its  maximum  possible  value  at a critical  value  of  r defined  by  lnr  +
                                                                                                   c
                            (1  -  r )/r c  = e . See also Problem  15B.4.
                                       v
                                c
                            (d)  Show  that, for  the adiabatic flow  of  an ideal  gas  with  constant C  in a horizontal duct  of
                                                                                   p
                            constant cross section, the d-iorm of the total energy balance (Eq. 15.4-4) simplifies  to
                                                      pV  + ^ - у Ч ^  2  = constant           (15B.3-5)
                                                          (
                            where  у  = C /C . Combine this result with  Eq. 15B.3-2 to get
                                      p  v
                                                         2 +                =  d6v            (15B3 6)
                                                          (      ^ - r )  7  ~                    "
                            Integrate this equation between  sections  1 and 2 enclosing  the resistance  e  assuming  у con-
                                                                                       vf
                            stant. Rearrange the result with the aid  of  the macroscopic mass balance to obtain the  follow-
                            ing relation for the mass flux G.
                                         /         PiPi
                              G = p№  =  /    —,    .  . .          (adiabatic flow of ideal gases)  (15B.3-7)
                                                                                      &
                                         e  -  [(y + l)/2y]ln  s  y-  I
                                                 1 W
                                          v
                                       \       f^s            2y
                            in which s  = (p /'P\) . 2
                                        2
                            (e)  Show  by  use  of  the macroscopic energy  and  mass  balances  that for  horizontal adiabatic
                            flow of ideal gases with constant y,

                                                                                               ( l 5 B 3  8 )
                                                                                                   -
                            This equation can be combined with  Eq. 15B.3-7 to show  that, as for isothermal flow, there is a
                            critical pressure ratio p /p\  corresponding to the maximum possible  mass flow rate.
                                              2
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