Page 578 - Bird R.B. Transport phenomena
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558   Chapter 18  Concentration Distributions in Solids  and in Laminar Flow

                                                          Fig. 18.5-1.  Absorption  of A  into a falling  film  of
                                                          liquid B.



                                 Ax
                           c A0

                                         Az

                              ill  w
                           v(x)



                           c A0






     §18.5  DIFFUSION INTO A      FALLING LIQUID
            FILM (GAS ABSORPTION)         1

                           In  this  section we  present  an illustration  of forced-convection  mass  transfer,  in which  vis-
                           cous  flow  and  diffusion  occur under  such  conditions that the velocity  field  can be  con-
                           sidered  virtually  unaffected  by  the diffusion.  Specifically,  we  consider  the absorption  of
                           gas  Л by  a laminar falling  film  of  liquid  B. The material A  is only slightly  soluble  in  B, so
                           that  the viscosity  of  the liquid  is  unaffected.  We  shall  make  the  further  restriction  that
                           the diffusion  takes  place so slowly in the liquid  film  that A  will not "penetrate" very  far
                           into the film—that  is, that the penetration distance will be small  in comparison with  the
                           film  thickness.  The system  is  sketched  in  Fig.  18.5-1. An  example  of  this  kind  of  system
                           occurs in the absorption  of O  in H O.
                                                   2    2
                              Let us  now  set up  the differential  equations  describing  the  diffusion  process.  First,
                           we  have  to solve the momentum transfer  problem  to obtain the velocity  profile  v (x)  for
                                                                                               z
                           the  film;  this has  already  been worked  out  in  §2.2  in the absence  of  mass  transfer  at the
                           fluid  surface,  and we  know  that the result  is


                                                       v {x)  =  v                             (18.5-1)
                                                       z      n
                           provided  that "end effects"  are ignored.
                              Next we  have  to establish  a mass  balance  on component A.  We  note that c A  will  be
                           changing  with  both  x  and  z. Hence, as  the element  of  volume  for  the mass  balance,  we
                           select the volume formed by  the intersection of a slab  of thickness  Az with  a slab  of  thick-
                           ness  Ax. Then the mass balance on A  over  this segment  of  a film  of width  W becomes

                                            WAx  -       WAx  +     WAz  -       WAz  =  0     (18.5-2)
                                       N Az \ z   N Az \ z+ b Z  N Ax \ x  N Ax \ x+Ax
                           Dividing  by  W  Ax  Az and  performing  the usual  limiting  process  as  the volume  element
                           becomes innnitesimally  small, we  get

                                                                                               (18.5-3)
                                                          dz    dx


                               1  S. Lynn, J. R. Straatemeier, and H. Kramers, Chem. Engr. Sci., 4,49-67  (1955).
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