Page 640 - Bird R.B. Transport phenomena
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620  Chapter 20  Concentration Distributions with  More Than One Independent  Variable

                               2)
                          and  a)  described  by
                               A
                                                                     2
                          P.D.E.:               - ^ -  +  (v  •  VOJ^) = 3) У ^ 2 )  -  к"'(off  (20.1-48)
                                                                  ЛВ
                          I.C.atf  =  0:                   ^  2 )  = 0                       (20.1-49)
                          B.C. at surfaces:                w?  = "AO (*, y.  z)              (20.1-50)

                          We  now  proceed to solve these two  auxiliary  problems by  means  of  Laplace  transform.
                             Taking  the Laplace transform  of the equations for  o)  gives
                                                                       ])
                                                                      A
                          P.D.E.  + I.C.:  (p + k"W A ])  -  o> {x, y, z)  + (v  •  VSJJ*)  = ЯЬ Ч п "  (20.1-51)
                                                                                2
                                                                              АВ
                                                        Al
                                                                                 А
                          B.C. at surfaces:                 п А ])  = 0                      (20.1-52)
                          Now,  the  function  g  in  Eq.  20.1-43  is  the  solution  for  a)  with  k"' replaced  by  zero. Corre-
                                                                        ])
                                                                        A
                          spondingly  the Laplace transform  g  satisfies  Eqs. 20.1-51 and 52 with  p  + k'" replaced by p:
                                                   uTty,  x, У, z)  = g(p  + k'", x, y, z)   (20.1-53)
                          Hence by  taking the inverse  Laplace transform we  get
                                                                   k"'t)                     (20.1-54)
                          which  is the first  part  of the solution.
                             Next, taking the Laplace transform  of  Eqs. 20.1-48  to 50 gives
                                                                  2)
                                                                          2
                          P.D.E.  + I.C.:       (p + k"W?  + (v  • V^ )  = °b V uf            (20.1-55)
                                                                        AB
                          B.C. at surfaces:             w?  = i  a) (x, y, z)                (20.1-56)
                                                               A0
                          The Laplace transform  /  satisfies  the same two  equations with  k"' replaced  by  zero. That is,  if
                          we now use  s  for  the transform  variable  in lieu  of p, we  have
                                                                       2
                          P.D.E.  + I.C.:             s/ +  (v  •  V/)  = 9) V ~f             (20.1-57)
                                                                    AB
                          B.C. at surfaces:             / =  ]• u) (x,  y, z)                (20.1-58)
                                                              AQ
                          We  see  that the function  sf  satisfies  the same boundary  condition as  puff  and  that the  differ-
                          ential equations for  sf  and puff  are identical when  s  = p  + k". Hence
                                                       V^A\  =  ^\S- ^                       (20.1-59)
                                                                 P
                          or

                                                ^ (р,  x, у, z)  =  V -^j f{p  + k"', x, y, z)  (20.1-60)
                                                 2 )
                                                                lr
                          Taking  the inverse  transform  then gives

                                                off  =  I* exp(-k"'t')  ^-f(x,  y, z, t'W    (20.1-61)
                                                     Jo         at
                                                                                        {
                          as  the second  part  of  the solution. Addition  of  the two parts  of  the solution, u>  and  off,  then
                                                                                         A
                          gives  Eq. 20.1-43  directly.
                             Equation  20.1-43  provides  a means  for  predicting  concentration profiles  in reacting  sys-
                          tems  from  calculations  or  experiments  on  nonreacting systems  at  the same  flow  conditions.
                          Several  extensions  of  this treatment are available, including multicomponent systems, 9  turbu-
                                 8 9
                                                                   7 9
                          lent  flow, '  and more general boundary conditions. "
                             9
                              Y.-H. Pao, A1AA Journal, 2,1550-1559 (1964); Chem. Eng. Sci., 19,694-696 (1964); ibid., 20, 665-669
                          (1965).
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