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            186   Chapter Seven


            Chemical Reactions/Basic Design
            The chemical reaction that occurs is best illustrated as follows:
            1. Reaction at the negative plate (pure lead)


                                Pb   H 2 SO 4 → PbSO 4   H 2
            2. Reaction at the positive plate (lead oxide)
                             PbO 2   H 2 SO 4 → PbSO 4   (2OH)

              Adding together 1 and 2 the chemical reaction for the cell is:

                         PbO 2   Pb   2H 2 SO 4 → 2PbSO 4   2H 2 O
              As the action proceeds and the discharge is complete, the plates are
            covered in the case of the negative plate with lead sulphate and the pos-
            itive plate with a mixture of lead compounds, PbO and PbSO.
              Recharging the cell involves converting the lead sulphate to lead.
            Thus, the reactions are now as follows:

                               PbSO 4   (2H) → H 2 SO 4   Pb

              The peroxide is regenerated as follows:

                             PbSO 4   (2OH) → PbO 2   H 2 SO 4
              The complete reaction is thus expressed as:

                         2PbSO 4   2H 2 O → Pb   PbO 2   2H 2 SO 4
              To all intents and purposes the efficiency of the reaction is 75 to 85
            percent, that is, the losses between discharge and recharge (Fig. 7.1).

             Electromotive force, e.m.f. (V)  2.4  Discharge
              2.6


                             Charge
              2.2
              2.0
              1.8
              1.6
              1.4
                0     20    40     60    80    100
                             Time (min)

            Figure 7.1


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