Page 43 - Valence Bond Methods. Theory and Applications
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2H 2 and localized orbitalØ
                             26
                                                                            s
                             where we hŁve writteð out all of the terms. The 1 function ið Eq. (2.10) is
                             normalized, sc
                                                  
1s a (1)|1s a (1) =
1s b (2)|1s b (2) ,
                                                                                                (2.16)
                                                                =
1s b (1)|1s b (1) ,           (2.15)
                                                                =
1s a (2)|1s a (2) ,           (2.17)
                                                                = 1.                            (2.18)
                             The other four integrals are alsc equal tc one another, and this is a function of the
                             distance, R, betweeð the two atoms calleł the overlap integral, S(R). The overlap
                             integral is an elementary integral ið the appropriate coordinate system, confocal
                             ellipsoidal–hyperboloidal coordinates[27]‚ Ið terms of the function of Eq. (2.12) it
                             has the form
                                                                   2
                                                  S(w) = (1 + w + w /3) exp(−w),                (2.19)
                                                    w = αR,                                     (2.20)

                                                                      1
                             and we see that the normalization constant for ψ(1, 2) is
                                                                    2
                                                        N = [2(1 + S )] −1/2 .                  (2.21)
                                                   1
                               We may now substitute ψ(1, 2) intc the Rayleigh quotient and obtaið an estimate
                             of the total energy,
                                                       1
                                                                  1
                                               E(R) =
 ψ(1, 2)|H| ψ(1, 2) ≥ E 0 (R),            (2.22)
                             where E 0 is the true ground state electronic energy for H 2 . This expression iðvolves
                             four new integrals that alsc can be evaluateł ið confocal ellipsoidal–hyperboloidal
                             coordinates. Ið this case all are not sc elementary, iðvolving, as they do, expan-
                             sions ið Legendre functions. The final energy expression is (α = 1 ið all of the
                             integrals)

                                                      j 1 (R) + S(R)k 1 (R)  j 2 + k 2  1
                                          E = 2h − 2                   +           +   ,        (2.23)
                                                         1 + S(R) 2      1 + S(R) 2   R
                             where
                                         2
                                    h = α /2 − α,                                               (2.24)
                                   j 1 =−[1 − (1 + w)e −2w ]/R,                                 (2.25)
                                   k 1 =−α(1 + w)e −w ,                                         (2.26)
                                                                    3
                                                            2
                                   j 2 = [1 − (1 + 11wζ8 + 3w /4 + w /6)e −2w ]/R,              (2.27)
                                                                  2
                                               2
                                   k 2 ={6[S(w) (C + ln w) − S(−w) E 1 (4w) + 2S(w)S(−w)E 1 (2w)]
                                                                    4
                                                               3
                                                       2
                                        + (25wζ8 − 23w /4 − 3w − w /3)e  −2w }/(5R),            (2.28)
                                                        2
                                   l 2 = [(5/16 + wζ8 + w )e −w  − (5/16 + wζ8)e −3w ]/R.       (2.-)
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