250 Well Logging and Formation Evaluation
We are in a Case D situation. The apparent formation dip is given by:
-
=
+
.
a= 6 2 90 95 1 2 degrees from Equation 13.5
.
Using Equation 13.6 with g= 40 degrees we find:
tan D) = tan . ) 2 cos(40 ) = . 0 027
(
(1
Hence D= 1.57 degrees.