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Section 4.2  Introduction to Tension Test                                  127

                                200

                                                            Fracture
                                150
                                                                    20
                               σ, Stress, MPa  100                      σ, ksi






                                 50        Gray cast iron           10


                                  0                                 0
                                            0.004      0.008      0.012
                                                 ε, Strain

                Figure 4.8 Stress–strain curve for gray cast iron in tension, showing brittle behavior.

                                            σ , ultimate
                                             u
                                                     σ , ε ,   fracture
                                                      f   f
                                               (c)
                                       (b)        (d)
                             σ, Stress  (a)  σ , yield
                                   o


                                      ε pf   , after fracture
                             0                            (a)  (b)  (c)  (d)
                                       ε, Strain
            Figure 4.9 Schematic of the engineering stress–strain curve of a typical ductile metal that
            exhibits necking behavior. Necking begins at the ultimate stress point.

            only after extensive deformation. Stress–strain curves for ductile behavior in engineering metals and
            some polymers are similar to Figs. 4.9 and 4.10, respectively.

            4.2.2 Additional Comments
            One might ask why we describe tension test results in terms of stress and strain, σ and ε, rather than
            simply force and length change, P and  L. Note that samples of a given material with different
            cross-sectional areas A i will fail at higher forces for larger areas. By calculating the force per unit
            area, or stress, this effect of sample size is removed. Hence, a given material is expected to have the
            same yield, ultimate, and fracture stress for any cross-sectional area A i , while the corresponding
            forces P vary with A i . (An actual experimental comparison for different A i will be affected by
            minor variations in properties with location in the parent batch of material, lack of absolute precision
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