Page 283 - Mechanical Behavior of Materials
P. 283

284                               Chapter 7  Yielding and Fracture under Combined Stresses


            where the subscript S specifies the maximum shear stress criterion. The safety factor against yielding
            is then
                                                    σ o
                                                X =                                   (7.22)
                                                     ¯ σ S
            7.4.2 Graphical Representation of the Maximum Shear Stress Criterion

            For plane stress, such as σ 3 = 0, the maximum shear stress criterion can be represented on a plot of
            σ 1 versus σ 2 , as shown in Fig. 7.5(a). Points on the distorted hexagon correspond to yielding, and
            points inside are safe. This failure locus is obtained by substituting σ 3 = 0 into the yield criterion
            of Eq. 7.20:

                                      σ o = MAX(|σ 1 − σ 2 | , |σ 2 | , |σ 1 |)       (7.23)

            The region of no yielding, where ¯σ S <σ o , is thus the region bounded by the lines
                                σ 1 − σ 2 =±σ o ,  σ 2 =±σ o ,  σ 1 =±σ o             (7.24)

            These lines are shown in Fig. 7.5(b). Note that the first equation gives a pair of parallel lines with a
            slope of unity, and the other two give pairs of lines parallel to the coordinate axes.
               For the general case, where all three principal normal stresses may have nonzero values, the
            boundaries of the region of no yielding are obtained from Eq. 7.20:

                            σ 1 − σ 2 =±σ o ,  σ 2 − σ 3 =±σ o ,  σ 1 − σ 3 =±σ o     (7.25)

            Each of these equations gives a pair of inclined planes which are parallel to the principal stress
            direction that does not appear in the equation. For example, the first equation represents a pair of
            planes parallel to the σ 3 direction.

                                                         σ  − σ  = − σ o
                                                             2
                                                          1
                                                                        σ = σ
                           σ 2                                           1  o
                  (a)                              (b)      σ
                                                             2             σ = σ o
                                                                            2
                          σ
                          o
                                                                             σ − σ = σ o
                                                                                  2
                                                                              1
                  − σ o
                           0       σ    σ 1                   0            σ 1
                                    o
                             − σ
                               o
                                              σ  = − σ
                                               2   o
                                                         σ = −σ
                                                          1   o
                Figure 7.5 Failure locus for the maximum shear stress yield criterion for plane stress.
   278   279   280   281   282   283   284   285   286   287   288