Page 103 - Introduction to Statistical Pattern Recognition
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3  Hypothesis Testing                                          85


                   3.3  Error Probability in Hypothesis Testing


                        Associated with  any decision rule  is  a probability of  error..  The proba-
                   bility  of  error is the most effective measure of  a decision rule's  usefulness.  In
                    general, the calculation of  error probability is very  difficult, although the con-
                   cept  is  quite  simple.  In  order  to  evaluate  (3.8),  we  must  perform  an  n-
                   dimensional integration in a complicated region.  A more promising procedure
                    is to determine the density function of the likelihood ratio, and integrate it in
                   the one-dimensional h-space, as in  (3.9) and  (3.10).  This  is possible for nor-
                   mal distributions, and will be discussed in this section.  However, if  the distri-
                   butions  are  not  normal,  finding  the  density  function  of  h  is  very  difficult.
                   Thus,  in  many  practical problems, we  either  employ experimental techniques
                    such as Monte Carlo simulation, or we  seek bounds on  the error probabilities.
                    We will discuss error bounds in the next section.


                    Linear Boundaries

                        When  the  distributions  are  normal  with  equal  covariance  matrices,
                   Zl Z2 = Z,  the minus-log  likelihood ratio becomes a linear function of X as
                      =
                    shown in (3.12).  Since (3.12) is a linear transformation from an n-dimensional
                    space to one-dimension, h(X) is a normal random variable when  X is a nor-
                   mally distributed random vector.  The expected value and variance of h (X) can
                   be calculated as follows:





                                                                               (3.96)


                    Since E { X I mi }  = Mi, (3.96) becomes

                                        I
                                  q, = --(A42   - MI)Y(M2 - M,) = -q  ,        (3.97)
                                        2
                                        1
                                  q2 =+-(A42   -M,)Y(M2 -M,)=+q.               (3.98)
                                        2

                    Also,
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