Page 242 - Materials Chemistry, Second Edition
P. 242

Groundwater Remediation                                          225



           extraction well is equal to ±Q/4Bu. In other words, the distance between the
           dividing streamlines at the line of the well is equal to Q/2Bu. The asymp-
           totic value of y (where x = ∞) is equal to ±Q/2Bu. Thus, the distance between
           the streamlines far upstream from the pumping well is Q/Bu.
             Note  that  the  parameter in  Equation (6.3), (Q/Bu),  has a  dimension  of
           length. To draw the envelope of the capture zone, Equation (6.3) can be rear-
           ranged as:

                                     y
                          x  =                 forpositive  y values
                                  +−
                             tan[ 1(  2 Bu  y )]π                          (6.4)
                                       Q
                                     y
                         x =                   fornegative  y values
                                 −−
                             tan[ 1(  2 Bu  y )]π                          (6.5)
                                       Q
           A set of (x, y) values can be obtained from these equations by first specifying
           a value of y. The envelope is symmetrical about the x-axis.

           Example 6.5:   Draw the Envelope of a Capture Zone of
                        a Groundwater Pumping Well
           Delineate the capture zone of a groundwater recovery well with the following
           information:

              •  Q = 60 gpm
              •  Hydraulic conductivity = 2,000 gpd/ft 2
              •  Groundwater gradient = 0.01
              •  Aquifer thickness = 50 ft

              Solution:
               (a)  Determine the groundwater velocity, u:
                   u = (K)(i) = [(2,000 gpd/ft )(1 day/1,440 min)(1 ft /7.48 gal)](0.01)
                                                             3
                                         2
                       	  	= 1.86 ×10  ft/min
                                    −3
               (b)  Determine the value of the parameter, Q/Bu:
                                          3
                        Q  =  (60gal/min)(1 ft /7.48gal)
                                          −3
                       Bu   (50ft)(1.86  × 10 ft/min)
                                          60 gal/min
                          =                                        = 86.4 ft
                                              2
                            (50ft)[(2,000 gal/d/ft )(1d/1, 440min)(0.01)]
               (c)  Establish a set of (x,  y) values using Equation (6.4). First
                   specify values of y (select smaller intervals for small y values).
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