Page 204 - A First Course In Stochastic Models
P. 204

LOSS MODELS                           197

                the rate at which the process leaves the set of states {i, i + 1, . . . , c} to the rate at
                which the process enters this set, we obtain the recursive equation

                                iµp i = (M − i + 1)αp i−1 ,  i = 1, . . . , c.

                This recursive equation allows for the explicit solution (verify):

                                     M   i      M−i

                                        p (1 − p)
                                     i
                             p i =                   ,  i = 0, 1, . . . , c,  (5.2.3)
                                   c
                                      M    k      M−k
                                         p (1 − p)
                                       k
                                  k=0
                where p is given by
                                                 1/µ
                                          p =           .
                                              1/µ + 1/α
                The distribution (5.2.3) is a truncated binomial distribution. To compute the fraction
                of service requests that are lost, we need the customer-average probabilities

                          π i = the long-run fraction of service requests that
                              find i busy channels upon arrival,  i = 0, 1, . . . , c.

                The π i are found by noting that

                      π i = (the long-run average number of service requests that are
                           generated per time unit and find i busy channels upon

                           arrival) (the long-run average number of service requests
                           that are generated per time unit).
                In state i, service requests are generated at a rate (M − i)α. Thus the arrival rate
                of service requests that see i busy channels equals (M − i)αp i . Hence

                                       (M − i)αp i
                               π i =   c           ,  i = 0, 1, . . . , c.
                                      k=0 (M − k)αp k
                It next follows from (5.2.3) that
                                M − 1   i     M−1−i

                                      p (1 − p)
                                  i
                        π i =                         ,  i = 0, 1, . . . , c.  (5.2.4)
                                 M − 1
                             c
                                         k      M−1−k
                                        p (1 − p)
                                   k
                            k=0
                It is a remarkable finding that the distribution {π i } is the same as the distribution
                {p i } except that M is replaced by M−1. In other words, the equilibrium distribution
                of the state just prior to the arrival epochs of new service requests is the same as
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