Page 227 - A First Course In Stochastic Models
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220 MARKOV CHAINS AND QUEUES
• A fixed number of M identical customers move around in the network.
• Each station is a single-server station with ample waiting room and at each
station service is in order of arrival.
• The service times of the customers at the different visits to the stations are
independent of each other, and the service time of a customer at station j has
an exponential distribution with mean 1/µ j for j = 1, . . . , K.
• Upon service completion at station i, the served customer moves with probability
p ij to station j for j = 1, . . . , K, where K p ij = 1 for all i = 1, . . . , K.
j=1
The routing matrix P = (p ij ), i, j = 1, . . . , K is assumed to be an irreducible
Markov matrix. Since the Markov matrix P is irreducible, its equilibrium distribu-
tion {π j } is the unique positive solution to the equilibrium equations
K
π j = π i p ij , j = 1, . . . , K (5.6.11)
i=1
K
in conjunction with the normalizing equation j=1 j = 1. The relative visit
π
frequencies to the stations are proportional to these equilibrium probabilities. To
see this, let
λ j = the long-run average arrival rate of customers at station j.
Since λ i is also the rate at which customers depart from station i, we have that
λ i p ij is the rate at which customers arrive at station j from station i. This gives
the traffic equations
K
λ j = λ i p ij , j = 1, . . . , K. (5.6.12)
i=1
The solution of the equilibrium equations (5.6.11) of the Markov matrix P is unique
up to a multiplicative constant. Hence, for some constant γ > 0,
λ j = γ π j , j = 1, . . . , K. (5.6.13)
Denote by X j (t) the number of customers present at station j at time t. The process
{(X 1 (t), . . . , X K (t))} is a continuous-time Markov chain with the finite state space
I = {(n 1 , . . . , n K ) | n i ≥ 0, K n i = M}.
i=1
Theorem 5.6.2 The equilibrium distribution of the continuous-time Markov chain
{X(t) = (X 1 (t), . . . , X K (t))} is given by
K
n k
π k
p(n 1 , . . . , n K ) = C (5.6.14)
µ k
k=1
for some constant C > 0.