Page 316 - Advanced Organic Chemistry Part B - Reactions & Synthesis
P. 316

288                   b. Suppose you had access to (+)-nonactic acid and the C(8) epimer of (−)-
                              nonactic acid, how could you obtain nonactin?
      CHAPTER 3
      Functional Group                   CH 3        O
      Interconversion                                                   CH 3
      by Substitution,                 O       O       O
      Including Protection and               H   H                   HO       O     CO 2 H
      Deprotection                  O              CH 3    CH 3             H   H
                                                                                  CH 3
                                         H           H                   (+)-nonactic acid
                                       OI             O
                                         H           H
                                                                        CH 3
                                            CH 3   CH 3
                                              H  H                   HO       O
                                  CH 3                     O                        CO 2 H
                                        O      O        O                   H   H CH 3
                                          O           CH 3
                                                                         (–)-nonactic acid
                                             Nonactin

                       3.22. Because they are readily available from natural sources in enantiomerically
                            pure form, carbohydrates are very useful starting materials for the synthesis of
                            other enantiomerically pure substances. However, the high number of similar
                            functional groups present in the carbohydrates requires versatile techniques for
                            protection and deprotection. Show how appropriate manipulation of protecting
                            groups and other selective reactions could be employed to effect the following
                            transformations.
                            (a)   HOCH 2
                                                   HOCH 2  O
                                  HOCH  O
                                                                 O
                                             O        HOCH     O    CH 3
                                    HOCH 2  O  CH 3        2     CH 3
                                             CH 3

                            (b)                       Ph
                                  HO
                                     CH 2 OH             O
                                        O               O
                                 HO                          O
                                     HO                O
                                         OCH 3    PhCH 2
                                                       PhCH 2 O
                                                              OCH 3
                            (c)  Ph   O                    CH 2 OCPh 3
                                     O      O        HO      O

                                          H C               H C
                                                             3
                                         O                O
                                      CH 3  3 OCH 3    CH 3    OCH3
                            (d)        OCH Ph
                                           2
                                                      O    OH
                                     O
                                         OH          OH
                                     OH          HO     OH
                                 HO
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