Page 284 - Advanced Thermodynamics for Engineers, Second Edition
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12.10 DISSOCIATION CALCULATIONS FOR THE EVALUATION            273




                                    0.7

                                   0.6

                                  Degree of dissociation, α   0.4  Carbon dioxide
                                   0.5



                                    0.3
                                                            Hydrogen
                                   0.2

                                    0.1

                                     0
                                     1000    1200    1400    1600    1800   2000
                                                   Temperature, T / (K)
               FIGURE 12.6
               Effect of temperature on degree of dissociation.




                  This chain of reactions has to include the formation of atomic oxygen and nitrogen and also the OH
               radical. To obtain an accurate prediction of the NO concentration a total of 12 species have been
               considered.
                                ½1Š H 2 O;  ½2Š H 2 ;  ½3Š OH;  ½4Š H;  ½5Š N 2 ;  ½6Š NO;
                                 ½7Š N;  ½8Š CO 2 ;  ½9Š CO;  ½10Š O 2 ;  ½11Š O;  ½12Š Ar:
                  The numbers in [ ] will be used to identify the species in later equations.
                  The formation and breakdown of these species are defined by the following set of equations.
                                                                         ffiffiffi
                                                                     ffiffiffiffiffi p
                                                                   p
                                   H 2 5 2H               Kp 1  ¼ðx 4 = x 2 Þ p
                                                                           ffiffiffi
                                                                      ffiffiffiffiffiffi p
                                   O 2 5 2O               K p2 ¼ðx 11 = x 10 Þ p
                                                                    p
                                                                         ffiffiffi
                                                                   p
                                                                     ffiffiffiffiffi p
                                   N 2 5 2N               K p3 ¼ðx 7 = x 5 Þ p
                                                                     2

                                 2H 2 O 5 2H 2 þ O 2      K p 4  ¼ x 10 b p
                                                                                          (12.106)
                                                                            ffiffiffi
                                                                       ffiffiffiffiffi p
                                                              ¼ðx 3 =ðb x 2 ÞÞ p
                                                                     p
                                 2H 2 O 5 2OH þ H 2       K p 5
                             CO 2 þ H 2 5 H 2 O þ CO      K p 6  ¼ bx 9 =x 8
                                                                            ffiffiffi
                                                                       ffiffiffiffiffi p
                                                                     p
                            2H 2 O þ N 2 5 2H 2 þ 2NO     K p 7  ¼ðx 6 =ðb x 2 ÞÞ p
               where b ¼ x 1 =x 2
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