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70     CHAPTER 2  Linear Second-Order Equations



                                                     0.8


                                                     0.4


                                                      0
                                                                4       8       12      16
                                                                        t
                                                    –0.4


                                                    –0.8

                                                    FIGURE 2.11 Beats.


                                                                A
                                                       y(t) =         [cos(ωt) − cos(ω 0 t)].
                                                                2
                                                            m(ω − ω )
                                                                    2
                                                                0
                                 The behavior of this solution reveals itself more clearly if we write it as
                                                         2A          1             1
                                                y(t) =          sin  (ω 0 + ω)t sin  (ω 0 − ω)t .
                                                         2
                                                      m(ω − ω )     2              2
                                                              2
                                                         0
                                 This formulation exhibits a periodic variation of amplitude in the solution, depending on the
                                 relative sizes of ω 0 + ω and ω 0 − ω. This periodic variation is called a beat. As an example,
                                                                                                        2
                                                                                                   2
                                 suppose ω 0 + ω = 5 and ω 0 − ω = 1, and the constants are chosen so that 2A/m(ω − ω ) = 1.
                                                                                                   0
                                 Now the displacement function is
                                                                      5t      t

                                                            y(t) = sin    sin    .
                                                                      2       2
                                 Figure 2.11 is a graph of this solution.

                                 2.4.5 Analogy with an Electrical Circuit

                                 In an RLC circuit with electromotive force E(t), the differential equation for the current is
                                                                        1

                                                          Li (t) + Ri(t) +  q(t) = E(t).
                                                                        C
                                 Since i = q , this is a second-order differential equation for the charge:

                                                                R     1     1

                                                           q +    q +    q =  E(t).
                                                                L     LC    L
                                 Assuming that the resistance, inductance, and capacitance are constant, this equation is exactly
                                 analogous to the spring equation with a driving force, which has the form

                                                                 c    k     1

                                                            y +   y +   y =   f (t).
                                                                m     m     m



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                                   October 14, 2010  14:12   THM/NEIL   Page-70         27410_02_ch02_p43-76
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