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5.4 EXAMPLES      107




                                      Temperature, T




                                          saturated liquid
                                          line      Q  in
                                           3                 4

                                                                  W T
                                         2
                                            W P      Q out
                                     o
                             T   =T =81.3  C  1            6     6 '    saturated vapour
                              01
                                 1
                                     o
                                T   =20  C                              line
                                  02
                                                                      Entropy, S
               FIGURE 5.4
               Temperature–entropy diagram for basic Rankine cycle.


                  Conditions at 6


                                         p 6 ¼ 0:5 bar; s 6 ¼ 6:340 kJ kg K:


                  t s ¼ 81:3 C; h g ¼ 2645 kJ kg; h f ¼ 340 kJ kg; s g ¼ 7:593 kJ kg K; s f ¼ 1:091 kJ kg K:
               thus
                                                6:340   1:091
                                            x 6 ¼           ¼ 0:8073
                                                7:593   1:091

                       h 6 ¼ x 6 h g þ 1   x 6 h f ¼ 0:8073   2645 þ 1   0:8073   340 ¼ 2200:8kJ kg
                  Conditions at 1

                                  p 1 ¼ 0:5 bar; s 1 ¼ 1:091 kJ kg K; h 1 ¼ 340 kJ kg:
                                  v 1 ¼ v f ¼ 0:001029 m 3   kg:

                  Conditions at 2

                                          p 2 ¼ 20 bar; s 2 ¼ 1:091 kJ kg K:
                             v 2 ¼ 0:001029 þ 0:2    0:0006   10  2    ¼ 0:001028 kJ kg K:


                  Hence feed pump work,
                                   w P ¼ w 12 ¼ vdp ¼ dh 12 :
                                      ¼ ð0:001029 þ 0:001028Þ=2   19:5   100 ¼ 2:005 kJ=kg:
                                   h 2 ¼ h 1 þ dh 12 ¼ 340 þ 2:005 ¼ 342:0kJ=kg:
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