Page 500 - Advanced thermodynamics for engineers
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492    CHAPTER 20 IRREVERSIBLE THERMODYNAMICS




             where
                 ~
                N ¼ Avogadro’s number.
                The groups of terms can be defined in the following way:


                                                 p   h density
                                                ~
                                                NkT
                                                   1=2

                                               kT
                                                      h velocity
                                               2m
                                                3
                                                 kT h energy:
                                                2
                                      ~ 1=2
                                                  ~
                                      Nm    and  4N  are weighting factors:
                                       p 1=2    3p 1=2
                Thus

                                          _ n c
                                            ¼ density   mean velocity:
                                          A
                                    E _
                                      ¼ density   mean velocity   mean energy
                                    A
                The weighting factors show that the particles passing through area A carry with them an unrep-
             resentative sample of the energy of the system from which they come.
                This example can be expanded into an apparatus which contains two systems separated by a porous
             wall. It will be assumed that the pores in the wall are much shorter than the mean free path of the
             molecules. The system is shown in Fig. 20.8. The gases on either side of the partition are the same, but
             one side of the system is heated and the other side is cooled.
                From Eqn (20.114) the net flux of molecules passing through the wall is given by

                                        0                    0
                                        _ n   _ n c     1=2  p    p
                                        c
                                              ¼ð2pkmÞ      p ffiffiffiffiffi   p ffiffiffiffi             (20.118)
                                          A                  T  0  T

                                               p             p'
                             .
                           Cooling                                         Heating
                                                                              .
                             - Q              T              T'              + Q

                                                      Porous
                                                        wall
             FIGURE 20.8
             Arrangement for flow through a porous plug.
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