Page 113 - Aerodynamics for Engineering Students
P. 113

96  Aerodynamics for Engineering Students







                                                                       h





                   Fig. 2.30



                   are parallel to the x axis, so v = 0. Therefore Eqn (2.93) implies du/dx = 0, i.e. u is a
                   function only of y. There is no external pressure field, so Eqn (2.92a) reduces to

                                         a2U
                                       p-   = 0  implying  u = Cly + C2              (2.106)
                                         dY2
                   where  C1  and  C2  are constants  of  integration.  u = 0  and  UT when y = 0 and  h
                   respectively, so Eqn (2.106) becomes




                   where T is the constant viscous shear stress.
                     This solution approximates well the flow between two concentric cylinders with the
                   inner one rotating at fmed speed, provided the clearance is small compared with the
                   cylinder’s radius, R. This is the basis of a  viscometer - an instrument for measuring
                   viscosity, since the  torque  required to rotate  the  cylinder at constant  speed w  is
                   proportional to T which is given by pwR/h. Thus if the torque and rotational speed
                   are measured the viscosity can be determined.


                   2.10.2  Plane Poiseuille flow - pressure-driven channel flow
                   This also corresponds to the flow between two infinite, plane, parallel surfaces (see
                   Fig. 2.31). Unlike Couette flow, both surfaces are stationary and flow is produced by
                   the application of pressure. Thus all the arguments used in Section 2.10.1 to simplify
                   the Navier-Stokes  equations still hold. The only difference is that the pressure term
                   in Eqn (2.95a) is retained so that it simplifies to

                                  dp    8%                    1 dPY2
                                - - + p-   = 0  implying  u = ---  + clY + c2        (2.108)
                                  dx    8y2                   pdx 2
                   The no-slip condition implies that u = 0 at y = 0 and h, so Eqn (2.108) becomes

                                                                                     (2.109)

                   Thus the velocity profile is parabolic in shape.
                     The true Poiseuille flow is found in capillaries with round sections. A very similar
                   solution can be found for this case in a similar way to Eqn (2.109) that again has
   108   109   110   111   112   113   114   115   116   117   118