Page 144 - Air Pollution Control Engineering

03_chap_wang.qxd 05/05/2004 12:48 pm Page 123
Cyclones 123

2
lb /ft s, and the cyclone inlet area has been calculated to be 2.41 ft ; determine the
m
following:
A. The August 1988 cost of the cyclone body
B. The August 1988 cost of the total cyclone system
C. The August 1990 cost of the total cyclone system
D. The present cost of the total cyclone system assuming that the present CE equipment
index obtained from Chemical Engineering (33) is 410.
Solution
A. The August 1988 cost of a cyclone is then obtained from Eq. (44) as follows:
P = 6250 A 0.9031
cyc cyc
(
P cyc = 6250 2.41) 0.9031
13
P cyc = US ,832
$
B. The August 1988 cost of a rotary air lock for this system is given by Eq. (45):

0.0985
P ral = 2730 A cyc
(
P ral = 2730 2.41) 0.0985
P = US $,977
2
ral
The August 1988 cost of a cyclone system is the sum of these two costs, or US$
16,809.
C. The February 1990 cost of a cyclone system is given by Eq. (57). The CE equipment
indices for August 1988 and February 1990 are 376.3 and 389.0, respectively, as
shown in Table 9:
cost = cost index b
b a
index a
cost = US$ 16,809 389.0
a
376.3
17
$
cost = US ,376 .0
a
D. The present cost (when the index is 410) is
cost = US$ 16, 809 410.0
b
376.3
cost = US$ 18, 314.35
b

Example 4
Determine the fan costs in July 1988 and in the future when the future CE equipment cost
index is projected to be 650.0. Assume the required static pressure equal 8 in. of water with
a fan diameter of 30 in.

Solution
Equation (46) can be used to obtain the fan cost as follows: