Page 145 - Air Pollution Control Engineering
P. 145
03_chap_wang.qxd 05/05/2004 12:48 pm Page 124
124 José Renato Coury et al.
P = 42.3 d 1.20
fan fan
(
P = 42.3 30) 1.20
fan
P fan = US $, 505
2
The future fan cost when the CE equipment cost index will reach 650.0. The July 1988
index is known to be 374.2. Equation (57) can be used for calculation:
cost = cost a index b
b
index
a
650.0
cost = US$ 2, 505
b
374.2
4
cost = US $, 351 .28 in the future
b
Example 5
Determine the required FRP duct diameter assuming a duct velocity (U ) of 2,000 ft/min,
duct
and an actual air emission rate (Q ) of 15,300 acfm.
a
Solution
d is obtained using Eq. (51):
duct
4 Q 0.5
d = 12 a
π U duct
duct
(
4 15, 300) 0.5
d = 12
( π 2, 000)
duct
d = 37.4 in. or 3.12 ft.
duct
Example 6
Determine the cost of a 50-ft FRP duct (D = 3.12 ft) in the future when the CE equipment
duct
cost index reaches 700.0.
Solution
The August 1988 cost of FRP ductwork can be calculated using Eq. (53):
P FRPd = 24 D duct
P FRPd = 24(3.12 )
P FRPd = US$ 74 .88 ft
Thus, for a 50-ft duct length, the August 1988 cost of ductwork equals 50(US$ 74.88) =
US$ 3,744.
The future cost when the CE equipment cost index reaches 700.0 is
cost = cost index b
b a
index a