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212 7 Combustion Process and Air Emission Formation
The net rate of NO formation under a constant pressure and temperature con-
dition can be calculated by considering all three step reactions in Table 7.5.
½
dNO
f
r NO ¼ ¼ k 1f N 2 O½ k 1b NO½ N½g
½
dt
ð7:57Þ
½
f
þ k 2f O 2 N½ k 2b NO½ O½g
f
þ k 3f N½ OH½ k 3b NO H½g:
½
When all the reactions in Table 7.5 reach equilibrium state, the NO formation
rate attributed to each of three step reactions can be described as, respectively,
½
r 1 ¼ k 1f N 2 O½ ¼ k 1b NO½ N½
e e e e
½
½
r 2 ¼ k 2f O 2 N½ ¼ k 2b NO O½ e ð7:58Þ
e
e
e
½
½
r 3 ¼ k 3f N½ OH ¼ k 3b NO H½ e
e
e
e
where the subscript e stands for equilibrium. For easy analysis, we also define two
dimensionless concentrations as follows.
½NO] ½N
a ¼ ; b ¼ ð7:59Þ
½ NO ½N
e e
Then the rate of NO formation before reaching equilibrium state Eq. (7.57) can
be rewritten as
r NO ¼ r 1 1 abð Þ þ r 2 b aÞ þ r 3 b aÞ ð7:60Þ
ð
ð
The concentration of N atoms is needed in order to solve this equation. By
similar approach, we can get the rate of N atom formation
ð
ð
r N ¼ r 1 1 abð Þ þ r 2 a bÞ þ r 3 a bÞ ð7:61Þ
By the pseudo-steady-state approximation, we can set the left hand side of
Eq. (7.61), r N ¼ 0, and it leads to
r 1 þ r 2 a þ r 3 a
b ¼ ð7:62Þ
r 1 a þ r 2 þ r 3
Substitute Eq. (7.62) into Eq. (7.60), and we have the corresponding rate of NO
formation as
2
ð
ð
2r 1 r 2 þ r 3 Þ 1 a Þ
r NO ¼ ð7:63Þ
ar 1 þ r 2 þ r 3