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7.7 NO x                                                        217

              The overall rate of NO formation from char-bound nitrogen is also described by
            Williams et al. [48]

                                             N ½Š char
                                     r NO ¼       r char                 ð7:83Þ
                                             C ½Š
                                               char
            where the reaction rate of char is

                                                      2      n
                              r char ¼ 254 exp  2:16   10  T P           ð7:84Þ
                                                           0
              The analysis above is also applicable to biomass combustion with the following
            differences. First of all, most (80 % or more) of the biomass is volatile and there is
            little char left. The combustion of char fraction is minor compared to volatile
            combustion.



            7.7.2 Nitrogen Dioxide

            The oxidation of NO leads to the formation of NO 2 through the overall reaction

                                1
                          NO þ O 2 $ NO 2
                                2
                                                                         ð7:85Þ

                                                6923         1=2
                                          4
                                ¼ 2:5   10  exp          atm
                          K P;NO 2
                                                 T
              The corresponding step reactions are
                           NO þ NO þ O 2 $ NO 2 þ NO 2
                                                                         ð7:86Þ
                                       3               6
                                           ð
                           k f ¼ 1:2   10 exp 530=TÞ  m mol   s
                       NO þ O þ M $ NO 2 þ M
                       (                                         )
                                    3                6
                         k f ¼ 1:5   10 exp 940=Tð  Þ  m mol   s         ð7:87Þ
                                    10                    3
                         k b ¼ 1:1   10 exp  33;000=Tð  Þ  m mol   s
              The conversion of NO to NO 2 can also take place when there are enough
            hydrogen peroxide radicals (HO 2 ).
                            NO þ HO 2 $ NO 2 þ OH
                                                                         ð7:88Þ
                                       6               3
                            k f ¼ 2:1   10 exp 240=Tð  Þ  m mol   s
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