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4.7  Solution of statically indeterminate systems  91

               loads in addition  to direct loads. It is usual, however, except for the thin-walled
               structures in Part I1 of this book, to ignore deflections produced by  shear forces.
               We only consider, therefore, bending and direct force contributions to the internal
               complementary energy of  such structures. The method of analysis is illustrated in
               the following example.

               Example 4.6
               The simply supported beam ABC shown in Fig. 4.16 is stiffened by an arrangement of
               pin-jointed bars capable of  sustaining axial loads only. If  the cross-sectional area
               of the beam is AB and that of the bars is A, calculate the forces in the members of
               the framework assuming that displacements are caused by bending and direct force
               action only.

                                 L /2    --      L/2











                                                            Cross- sectional

                                  E   R        R  D
               Fig. 4.16  Analysis of a trussed beam by the method of complementary energy.

                 We observe that if the beam were only capable of supporting direct loads then the
               structure would be a relatively simple statically determinate pin-jointed framework.
               Since the beam resists bending moments (we are ignoring shear effects) the system
               is  statically indeterminate with  a  single redundancy, the  bending moment at  any
               section of  the beam. The total complementary energy of the framework is given,
               with the notation previously developed, by




               If we  suppose that the tensile load in the member ED is R then, for  C to have a
               stationary value

                                                                                    (ii)

              At this point we assume the appropriate load-displacement  relationships; again we
               shall take the system to be linear so that Eq. (ii) becomes

                                                   li  FiLi 3Fi
                                                                                    (iii)
                                                   2=1
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