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86  Energy methods of structural analysis

                                            B            C















                  Fig. 4.12  Analysis of a statically indeterminate framework by the method of complementary energy.
                  a variety of statically indeterminate structures, beginning with the relatively simple
                  singly-redundant pin-jointed frame shown in Fig. 4.12 in which each member has
                  the same value of the product AE.
                    The first step is to choose the redundant member. In this example no advantage is
                  gained  by  the  choice  of  any  particular  member,  although  in  some cases careful
                  selection can result in a decrease in the amount of arithmetical labour. Taking BD
                  as the redundant member we  assume that it sustains a tensile force R due to the
                  external loading. The total  complementary energy of the  framework is, with the
                  notation of Eq. (4.15)

                                            C = 21:  AidFi - PA
                                                i=  1
                  Hence
                                                        dFi
                                             dC
                                             -        Ai - 0                         (4.21)
                                                =
                                                           =
                                             dR    .    dR
                                                   1=  1
                  or, assuming linear elasticity
                                              I  k      dFi
                                             -E  F       ~  = o  L  ~   ~            (4.22)
                                             AE.
                                                 1=1
                  The solution is now completed in Table 4.2  where, as in Table 4.1,  positive signs
                  indicate tension.

                  Table 4.2
                  0            0            0
                  Member       Length       F
   97   98   99   100   101   102   103   104   105   106   107