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216   CHAPTER 5 LINEAR PROGRAMMING: THE SIMPLEX METHOD


                    Can you find basic and  foundatanextremepoint.Becauseevery extreme point corresponds to a basic feasible
                    basic feasible solutions  solution, we can now conclude that the HighTech problem does have an optimal basic
                    to a system of equations      2
                    at this point? Try  feasible solution. The Simplex method is an iterative procedure for moving from one
                    Problem 1.       basic feasible solution (extreme point) to another until the optimal solution is reached.



                               5.2    Tableau Form


                    In geometry, a simplex is  With the Simplex method, an LP problem and its iterative solutions are usually
                    an n dimensional  presented in tables, or tableau formats. Each tableau represents a basic solution
                    equivalent of a two  from the Simplex procedure. The tableau also provides a convenient method of
                    dimensional triangle, so
                    the Simplex method is  identifying whether a potentially improved solution exists. If we take our standard
                    really looking for the  LP format from the HighTech problem we have:
                    corner points in n
                    dimensions.                         Max: 50x 1 þ 40x 2 þ 0s 1 þ 0s 2 þ 0s 3
                                                        s:t:
                                                                                    ¼ 150
                                                             3x 1 þ 5x 2 þ 1s 1
                                                                  1x 2    þ 1s 2    ¼ 20
                                                                               þ 1s 3 ¼ 300
                                                             8x 1 þ 5x 2
                                                              x 1 ; x 2 ; s 1 ; s 2 ; s 3   0
                                     In tabular form we can show this as:

                                                                                                      Value
                                                           x 1      x 2     s 1      s 2     s 3
                                      Objective function   50       40       0        0       0
                                      Constraint 1          3        5       1        0       0        150
                                      Constraint 2          0        1       0        1       0         20
                                      Constraint 3          8        5       0        0       1        300



                                     All we have done is to show the coefficients for the objective function and each
                                     constraint on separate rows with the appropriate value of each in the final column of
                                     the tableau. To help us remember what each column of the tableau relates to, we
                                     have shown the variable associated with each column at the top of the tableau.
                                       Later on, we will want to be able to refer to groups of coefficients (all those for
                                     the objective function, all those for the constraint coefficients and all those for the
                                     right-hand side values). We use matrix notation where:
                                          c row   ¼ the row of objective function coefficients
                                          b column ¼ the column of right-hand side values of the constraint
                                                    equations
                                          A matrix ¼ the m rows and n columns of coefficients of the variables in
                                                    the constraint equations

                                     Using this notation, we would have a tableau:

                                                                c row
                                                                A matrix  b column

                                     2
                                     We are only considering cases that have an optimal solution. That is, cases of infeasibility and unboundedness
                                     will have no optimal solution, so no optimal basic feasible solution is possible.



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