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218   CHAPTER 5 LINEAR PROGRAMMING: THE SIMPLEX METHOD


                    The simplex tableau is  row associated with the basic variable. In the tableau, row 2 is associated with
                    nothing more than a table  basic variable s 1 because this row has a 1 in the unit column corresponding to s 1 .
                    that helps keep track of
                    the simplex method  So, the value of s 1 is given by the right-hand side value b 1 : s 1 ¼ b 1 ¼ 150. In a
                    calculations.    similar fashion, s 2 ¼ b 2 ¼ 20, and s 3 ¼ b 3 ¼ 300.
                    Reconstructing the  If we study the standard-form representation of the HighTech constraint equa-
                    original problem can be  tions closely, we can identify two properties that make it possible to find an initial
                    accomplished from the
                    initial simplex tableau.  basic feasible solution. The first property requires that the following conditions be
                                     satisfied:
                                     a. For each constraint equation, the coefficient of one of the m basic variables in
                                       that equation must be 1, and the coefficients for all the remaining basic variables
                                       in that equation must be 0.
                                     b. The coefficient for each basic variable must be 1 in only one constraint
                                       equation.

                                     When these conditions are satisfied, exactly one basic variable with a coefficient of 1
                                     is associated with each constraint equation, and for each of the m constraint
                                     equations, it is a different basic variable. Thus, if the n–m non-basic variables are
                                     set equal to zero, the values of the basic variables are the values of the right-hand
                    Try Problem 5(a) for  sides of the constraint equations.
                    practise in setting up the  The second property that enables us to find a basic feasible solution requires the
                    complete initial simplex  values of the right-hand sides of the constraint equations to be nonnegative. This
                    tableau for a problem
                    with less-than-or-equal-  nonnegativity ensures that the basic solution obtained by setting the basic variables
                    to constraints.  equal to the values of the right-hand sides will be feasible.
                                       If a linear programming problem satisfies these two properties, it is said to be in
                                     tableau form.




                               5.4    Improving the Solution

                                     Having found a basic feasible solution, the Simplex procedure now searches for an
                                     improved solution. The general principle is simple: will we get an improved,
                                     feasible solution if we add one of the non-basic variables to the current solution?
                                     In our HighTech problem, this would mean adding either variable x 1 or x 2 to the
                                     current solution (since these are the two non-basic variables). Effectively, this
                                     would mean letting either x 1 or x 2 take a nonzero value (or, in a business context,
                                     that we decide to produce some number of units of either the Deskpro model or
                                     the UltraPortable).
                                       Referring to Figure 5.1, our initial solution puts us at Point 1 on the graph (the
                                     origin where both decision variables are zero). The Simplex procedure now deter-
                                     mines whether a move to an adjacent corner point (either Point 5 or Point 2), would
                                     give an improved solution. (Note that Points 3 and 4 are not considered at this time
                                     since they are not adjacent to the current solution at Point 1.) However, if we were
                                     to introduce one of the non-basic variables into the solution then we would have to
                                     remove one of the existing basic variables – one of s 1 , s 2 or s 3 would then take a zero
                                     value.
                                       To help decide whether an improved solution is possible and determine which
                                     variables would be part of the solution and which would leave, we add some addi-
                                     tional information to the Simplex tableau. To help with the Simplex calculations, we
                                     first add two more rows to the tableau.






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