Page 469 -
P. 469

DEVELOPMENT OF THE OPTIMAL ORDER QUANTITY (Q) FORMULA FOR THE EOQ MODEL  449




                        Managerial Report                             unit in order to cover the daily absences? These
                                                                      extra daily needs will be filled by the additional
                        Develop a report that will enable the Fire Chief to
                                                                      firefighters and, when necessary, the more
                        determine the necessary numbers for the Fire
                                                                      expensive use of overtime by off-duty firefighters.
                        Department. Include, at a minimum, the following
                                                                    3 On a given day, what is the probability that Kelley-
                        items in your report.
                                                                      day firefighters will be called in to work overtime?
                        1 Assuming no daily absences and taking into
                                                                    4 Based on the three-unit organization, how
                          account the need to staff Kelley days, determine the
                                                                      many firefighters should be assigned to each
                          base number of firefighters needed by each unit.
                                                                      unit? What is the total number of full-time
                        2 Using a minimum cost criterion, how many    firefighters required for the River City Fire
                          additional firefighters should be added to each  Department?





                                        Development of the Optimal Order Quantity (Q) Formula for
                       Appendix 10.1
                                        the EOQ Model


                                      You will need to be familiar with differential calculus for this Appendix 10.1 and
                                      10.2. Given Equation (10.4) as the total annual cost for the EOQ model,


                                                                       1      D
                                                                   TC ¼ QC h þ  C o                    (10:4)
                                                                       2      Q

                                      we can find the order quantity Q that minimizes the total cost by setting the
                                      derivative, dTC/dQ, equal to zero and solving for Q*.
                                                                 dTC   1     D
                                                                     ¼ C h     C o ¼ 0
                                                                  dQ   2    Q 2
                                                                 1     D
                                                                   C h ¼  C o
                                                                 2     Q 2
                                                                    2
                                                                C h Q ¼ 2DC o
                                                                    2
                                                                  Q ¼  2DC o
                                                                        C h
                                      Hence,


                                                                         s ffiffiffiffiffiffiffiffiffiffiffiffi

                                                                     Q ¼   2DC o                       (10:5)
                                                                            C h

                                      The second derivative is:

                                                                      2
                                                                     d TC  2D
                                                                         ¼    C o
                                                                     dQ 2  Q 3
                                      Because the value of the second derivative is greater than zero, Q*from equation
                                      (10.5) is the minimum cost solution.






                Copyright 2014 Cengage Learning. All Rights Reserved. May not be copied, scanned, or duplicated, in whole or in part. Due to electronic rights, some third party content may be suppressed from the eBook and/or eChapter(s). Editorial review has
                      deemed that any suppressed content does not materially affect the overall learning experience. Cengage Learning reserves the right to remove additional content at any time if subsequent rights restrictions require it.
   464   465   466   467   468   469   470   471   472   473   474