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450   CHAPTER 10 INVENTORY MODELS



                                      Development of the Optimal Lot Size (Q*) Formula for the
                     Appendix 10.2
                                      Production Lot Size Model

                                     Given Equation (10.15) as the total annual cost for the production lot size model,


                                                                  1     D       D
                                                             TC ¼    1    QC h þ  C o               (10:15)
                                                                  2     P       Q


                                     we can find the order quantity Q that minimizes the total cost by setting the
                                     derivative, dTC/dQ, equal to zero and solving for Q*.

                                                            dTC  1     D      D
                                                               ¼    1     C h þ  C o ¼ 0
                                                            dQ   2     P      Q 2
                                     Solving for Q*, we have:

                                                              1    D       D
                                                                1     C h ¼  C o
                                                              2    P      Q 2

                                                                 D
                                                                       2
                                                              1     C h Q ¼ 2DC o
                                                                 P
                                                                       2
                                                                      Q ¼    2DC o
                                                                          ð1   D=PÞC h
                                     Hence,
                                                                     s ffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffiffi

                                                                Q ¼      2DC o                      (10:16)
                                                                       ð1   D=PÞC h

                                     The second derivative is:
                                                                    2
                                                                   d TC  2DC o
                                                                        ¼
                                                                    dQ 2   Q 3
                                     Because the value of the second derivative is greater than zero, Q*from equation
                                     (10.16) is a minimum cost solution.





























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