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                       112                       Applied Process Design for Chemical and Petrochemical Plants

                        10. Calculate the area required using Equation 10-9.  (Note: disregard sign)
                        11. Calculate the net available area in the assumed unit,   t c   15°
                           using only the effective tube length.
                                                                              t h   81°
                        12. Compare values calculated in steps 10 and 11. If the cal-
                           culated unit is too small, re-assume a new larger unit for   t c     15    0.815
                           step 3 or try closer baffle spacing in step 7 but do not   t h  81
                                              1
                           get baffles closer than  / 5 the shell I.D.
                                                                               Reading Figure 10-38,
                        13. Calculate the percent of excess area. A reasonable fig-
                           ure is 10—20%.                                          F   0.32
                        14. Calculate the shell-side pressure drop. (Refer to the  Then: t h   105   0.32(176   105)   127.7°F
                           later section on “Pressure Drop Relations” and Figure
                                                                             Note that the arithmetic average [ / 2 (176   105)   105
                                                                                                       1
                           10-140. If  P is too high, reassume unit (step 3).
                                                                             140°F] would be quite satisfactory for this design, because the
                        15. Calculate the tube-side pressure drop. (Use Figure 10-
                                                                             properties do not vary significantly with temperature.
                           139 for the end return losses. For water in tubes, use
                           Figure 10-138 for tube losses. For other liquids and
                                                                               1. Heat duty   (6350) (176   105) (0.33)
                           gases in tubes, use Figure 10-137.
                                                                                            150,000 Btu/hr
                           Total pressure drop   (end return   tube) losses, psi.
                                                                               2. Estimated unit
                         If the tube-side pressure drop exceeds a critical allowable
                                                                             Assume: U   100
                       value for the process system, then recheck by either lower-  LMTD   39.2
                       ing the flow rate and changing the temperature levels or
                       reassume a unit with fewer passes on tube side or more tubes
                                                                                   150,000
                       per pass. The unit must then be rechecked for the effect of   A       38.2 ft 2
                                                                                  11002139.22
                       changes on heat transfer performance.
                                                                             Tubes: 1-in. O.D.   14 BWG   8 ft long
                               Example 10-9. Convection Heat Transfer
                                        Exchanger Design                      No. required          38.2
                                                                                                  2
                                                                                           10.2618 ft >ft2 18   6 in.>122
                         See Figure 10-65.                                                  20 tubes
                         The liquid bottoms from a distillation column must be
                       cooled from 176°F to 105°F. The cooling water is untreated  Trial:
                       at 90°F.
                                                                                                                   1
                                                                               10-inch I.D. shell with 24 1-in. tubes on 1  / 4 -in. triangu-
                           Operating data: Bottom flow, 6,350 lb/hr          lar pitch, 4 tube passes.
                           Average Cp, 0.333 Btu/lb (°F)
                                                   2
                           Average k a , 0.055 Btu/hr (ft ) (°F/ft)            3. Log mean temperature difference (Figure 10-33),
                           Average  , 0.404 centipoise
                           Average sp.gr, 0.78                               176°    cooling    105°
                           Physical properties are based on values at 140°F average  95°  warming  90°
                           temperature.                                       81°                15°
                           Caloric fluid temperature for property evaluation can
                         be calculated from Equation 10-21.                    4. Water rate,

                       The caloric value of hot liquid on the shell side is
                                                                                   150,000
                                                                             w                30,000 lb>hr
                                                                                 112195   902
                       t h      t h2      F1t h1      t h2 2
                                                                                     30,000
                                                   150,000                   gpm              60
                       Rough estimate U c  at cold end       262                    18.3321602
                                                  138.22115°2
                                                                               24
                                                                             At  / 4   6 tubes/pass,
                                     150,000
                       U h  at hot end         48.5
                                     38.2181°2                                                      0.546         2
                                                                             Cross-sectional area/tube      0.00379 ft >tube
                                                                                                    144
                           U h   U c  48.5   262
                       C                        0.815                                                             2
                              U c       262                                  Flow area/pass = (0.00379)(6 tubes)   0.0227 ft flow area
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