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390    MATRICES AND EIGENVALUES
                             spring          spring
                            constant  x 1 (t)  constant  x 2 (t)
                              k 1              k 2
                                      m 1              m 2

                           Figure 8.3 An undamped mass–spring system.

           Noting that the solution of Eq. (8.5.7) can be written as Eq. (8.5.8) in terms of
           the eigenvectors of the system matrix, we write the solution of Eq. (8.6.1) as
                               2
                                                    w 1 (t)
                        x(t) =   w n (t)v n = [ v 1  v 2 ]  = V w(t)     (8.6.3)
                                                    w 2 (t)
                              n=1
           and substitute this into Eq. (8.6.1) to have

                       2               2                 2
                                                 (8.6.2)
                                                                 2
                         w (t)v n =−A             =   −                  (8.6.4)
                           n             w n (t)v n        w n (t)ω v n
                                                                 n
                      n=1             n=1               n=1
                                     2
                           w (t) =−ω w n (t)   for n = 1, 2              (8.6.5)
                                     n
                             n
           The solution of this equation is

                                    w (0)
                                      n
              w n (t) = w n (0) cos(ω n t) +  sin(ω n t)  with ω n =  λ n for n = 1, 2
                                      ω n
                                                                         (8.6.6)
                                                  T
           where the initial value of w(t) = [w 1 (t) w 2 (t] can be obtained via Eq. (8.6.3)
           from that of x(t)as
                       (8.6.3)  −1  (8.4.1)  T
                                                              T

                 w(0)   =   V  x(0)  =   V x(0),     w (0) = V x (0)     (8.6.7)
           Finally, we substitute Eq. (8.6.6) into Eq. (8.6.3) to obtain the solution of
           Eq. (8.6.1).
           PROBLEMS
           8.1 Symmetric Tridiagonal Toeplitz Matrix

               Consider the following N × N symmetric tridiagonal Toeplitz matrix as
                                                       
                                      a  b  0   ··  0  0
                                      b  a  b  ··  0  0  
                                    
                                     0  b  a   ··  0  0 
                                                        
                                                       
                                      ·  ·  ·   ··  ·  ·                (P8.1.1)
                                                       
                                                       
                                      ·  ·  ·   ··  ·  ·
                                                       
                                                       
                                      0  0  0   ··  a  b
                                                       
                                      0  0  0   ··  b  a
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