Page 103 - Applied Process Design For Chemical And Petrochemical Plants Volume II
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92                        Applied Process Design for Chemical and Petrochemical Plants

                                                                 Neglect the heavier than perchlor components in the
                                                               recufying section.
                                                                 In order to carry the perchlor it is assumed at 0.0001
                                                               mol fraction in overhead and reflux, the P-Tri is reduced
              1.4           0                 XI         co    to 0.0005 mol fraction for these calculations being tighter
              1.6           0.0768          0.346      29      specifications  than  the  initial  calculated  balance.  The
              2.0           0.20            0.445      23.5    overall effect will be small.
              3.0           0.40            0.312      18.8
              4.0           0.52            0.245      17
               00            -               -         12.6
           These values are plotted in Figure 8-52. From the curve,   A   0.9994    975.02   0.9984   545.5   0.9971
         the  operating  (L/D),  was  selected, and  the  theoretical   B   0.0005    1.00   0.001024   1.0   0.001828
         stages corresponding are 19.                              C      0.0001      0.273  0.000280   0.359  0.000656
                                                                                 L = 976.293  0.999704  546.859
         Tray-&Tray  Calculation-Ackers  and Wa& Method                                      (close
                                                                                            enough)
         Rectlfyng Section, (L/D),  = 3:l
         Light key = Trichlor; Heavy key = fi Tn               Typical calculations:
           Relative Volatilities to start: Use average of top and feed

                                      "a%
                             A        2.05
                             B        1.00
                                                                                            1
                             C       0.734                              1  (3) (0.9994) + 0.9994
                                                                (:),=-[   2.05  (3) (0.0005) 0.0005  = 975.02
                                                                                     +
                                                                Component B:
                                                                                           1
                                                                            3 (0.0005) + 0.0005 = l.oo
                                                                            3 (0.0005) + 0.0006

                                                                Component C:
                                                                                            1
                                                                            [
                                                                (:)   = - (0.0003) + 0.0005
                                                                         1
                                                                             3 (0.0001) + 0.0001  = o.272
                                                                             3
                                                                       0.734
                                                                 (XA)
                                                                    1 = 975.02/976.293 = 0.9984
                                                                 (xB)~ 1.00/976.293 = 0.001024
                                                                     =
                                                                 (%)I  = 0.273/976.293 = 0.000280
                                                                Tray 2: Component A
                                                                                            1
                                                                                     +
                                                                             3 (0.9984) 0.9994  = 543.5
                                                                                     +
                                                                            3 (0.00102) 0.0005
                                                                Component B
                                                                                            1
                                                                            3 (0.00102) + 0.0005 = l.oo
                                                                                     +
                                                                            3 (0.00102) 0.0005
                                                                Component C
                                Reflux  Ratio,  L/D
                                                                             3 (0.00028) + 0.0001 = o.359
            Figure 8-52. Gilliland Plot for multicomponent Example 8-28.      3  (0.0005) + 0.0005  1
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