Page 122 - Applied Process Design For Chemical And Petrochemical Plants Volume II
P. 122

Distillation                                          111

                  Sometimes the last term on right can be neglected.      At lean end, Yi  = 0 (or nearly so in most cases); if
                7. Calculate number of theoretical trays, M.            not, plot accordingly.

                                                         (8 - 205)   Stripping-Determine  Stripping-Medium Rate For Fixed
                                                                   Recovery [18]


                                                         (8 - 206)   1. The composition and  quantity of  rich oil, and per-
                                                                       cent  recovery  of  a  specified  key  component  are
                                                                       known, also column pressure and temperature.
                8. Actual trays at operating reflux:                 2. Using  Figure  8-58, assume  a  value  for  theoretical
                                                                       plates,  read S,  corresponding to  specified value  of
                        M
                  M.  =A                                 (8 - 207)     recovery E,i  for key component, since:
                    dCt
                         EO
                9. Calc-date for  each  component  corrected  amount    E s- - (SM+l - S)/(S'+l  - 1)
                  stripped:                                            Note that with this procedure, the effect of the num-
                    For each component:                                ber of theoretical plates available can be determined.
                                                                       In an existing column where the number of trays are
                                                         (8 - 208)     fmed, the theoretical trays can be obtained by  evalu-
                                                                       ating an efficiency for the system.
                                                                     3. The value of  S,  = Si for key component obtained in
                  (Vo/Lo)oper = fixed in Step 5.                       Step 2 is equal to

                  (1 + mi) and  (1 + ZXi) come from Step 6.
               10. From Figure 8-58, read (SM + ' - S)/S'+  ' - 1) = Esi
                  for each component at the fured theoretical required
                  trays and at individual Si values.                   Using key component:
               11. For final detail, recalculate mols stripped per hour
                  from new E,i  values and the total quantities of each
                  component in the incoming rich oil. If values do not
                  check exactly, adjustments can  be  made  in  steam
                  rate and XYi  to give exact values. In many cases this   Set up table: use I&  for each component to calcu-
                  accuracy is not justified since the method is subject   late Column 4.
                  to some deviation from theoretically correct values.
                                                                                                  .
                                                                                                 .
               12. A graphical solution is presented by Edmister [18]   Corn-   Mols/hr   QatCol.  { Vo (1 + ZYi))   Mols/hr
                  and handled like stepwise distillation.          ponent   inRichOd   Cond.   I$  b(l+m  &i   Stripped
                    Equilibrium line: starts at origin of X-Y plot.   -       -       ,...        ~  -     -  -
                                                                                                            ~
                    For assumed X values, calculate Y corresponding   -       -        -          -        -  -
                                                                                       -
                  for key component from                             -        -        -          -        -  -
                                                                              z                                  z
                                                                                      ~
                                                                         From values of  Si calculated (=S,) , read E,i  values
                  At lean oil end of tower: ZZi = 0 and XYi  = 0.      from Figure 8-58 at the number of  theoretical trays
                  Slope of equilibrium line is Y/X  = K,               assumed in Step 2. Note that the S,  corresponds to
                  At rich oil end of tower:                            the number of  trays selected, hence will give a value
                                                                       for performance of the system under these particular
                                                                       conditions.
                                                          -
                                                         (8 209)
                                                                     4. Calculate the mols of each component stripped/hr
                  Where Xi, XXi and XYi are known. R = rich end.
                  Operating line:
                                                                     5. Calculate, V,,  mols/hr. of stripping medium required
                                   Mols lean oil leaving stripper      (steam or gas)
                  Slope = Lo /Vo  =
                                Mols stripping steam (or gas) entering
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