Page 176 - Applied statistics and probability for engineers
P. 176

154     Chapter 4/Continuous Random Variables and Probability Distributions




                 Mind-Expanding Exercises

                 4-227.  The steps in this exercise lead to the probability den-  4-232.  Determine the mean and variance of a beta random
                 sity function of an Erlang random variable Xwith parameters   variable. Use the result that the probability density function

                              x e
                 λ and r, f x ( ) = λ r r−1  −   x λ  ( /  r − )!  , x > , and r = 1 , ,….  integrates to 1. That is,
                                                      2
                                             0
                                        1
                                                  (
                 (a)  Use the Poisson distribution to express P X >  x).  Γ( ) Γ( )  1  x α−1 ( − x )  for α > , > 0.
                                                                    β
                                                                                         β
                                                                 α
                                                                                β−1
                                                                                       0
                                                                            1
                                                                   +
                 (b) Use the result from part (a) to determine the cumulative   Γ(α β  )  = ∫ 0
                    distribution function of X.                 4-233.  The two-parameter exponential distribution uses a dif-
                                                                                                    γ
                 (c)  Differentiate the cumulative distribution function in part (b)   ferent range for the random variable X, namely, 0 ≤ ≤ x for
                    and simplify to obtain the probability density function of X.  a constant γ (and this equals the usual exponential distribution
                 4-228.  A bearing assembly contains 10 bearings. The bearing   in the special case that γ = 0). The probability density func-
                                                                                               γ
                                                                tion for X is f x( ) = λ  exp[−λ  x ( − γ )] for 0 ≤ ≤ x and 0 < λ.
                 diameters are assumed to be independent and normally distrib-
                 uted with a mean of 1.5 millimeters and a standard deviation   Determine the following in terms of the parameters λ and γ:
                                                                                                  γ
                                                                                                    1
                                                                                              (
                 of 0.025 millimeter. What is the probability that the maximum   (a)  Mean and variance of X.  (b) P X < + / λ )
                 diameter bearing in the assembly exceeds 1.6 millimeters?  4-234.  A process is said to be of six-sigma quality if the pro-
                 4-229.  Let the random variable X  denote a measurement  cess mean is at least six standard deviations from the nearest
                 from a manufactured product. Suppose that the target value for   speciication. Assume a normally distributed measurement.
                 the measurement is m. For example, X could denote a dimen-  (a) If a process mean is centered between upper and lower
                 sional length, and the target might be 10 millimeters. The   speciications at a distance of six standard deviations from
                 quality loss of the process producing the product is deined to   each, what is the probability that a product does not meet
                                   (
                                         2
                 be the expected value of k X −  m) , where k is a constant that   speciications? Using the result that 0.000001 equals one
                 relates a deviation from target to a loss measured in dollars.  part per million, express the answer in parts per million.
                 (a) Suppose that X  is a continuous random variable with  (b)  Because it is dificult to maintain a process mean centered
                    E X ( ) =  m and V X ( ) = σ . What is the quality loss of the   between the speciications, the probability of a product
                                     2
                    process?                                       not meeting speciications is often calculated after assum-
                 (b) Suppose that X  is a continuous random variable with  ing that the process shifts. If the process mean positioned
                                     2
                    E X ( ) = μ and V X ( ) = σ . What is the quality loss of the   as in part (a) shifts upward by 1.5 standard deviations,
                    process?                                       what is the probability that a product does not meet speci-
                 4-230.  The lifetime of an electronic ampliier is modeled   ications? Express the answer in parts per million.
                 as an exponential random variable. If 10% of the ampliiers   (c)  Rework part (a). Assume that the process mean is at a
                 have a mean of 20,000 hours and the remaining ampliiers   distance of three standard deviations.
                 have a mean of 50,000 hours, what proportion of the ampli-  (d) Rework part (b). Assume that the process mean is at
                 iers will fail before 60,000 hours?               a distance of three standard deviations and then shifts
                 4-231.  Lack of Memory Property. Show that for an expon-  upward by 1.5 standard deviations.
                                    (
                 ential random variable X, P X < 1 +  t 2  u X > 1) = (  t  (e)  Compare the results in parts (b) and (d) and comment.
                                        t
                                                    P X < 2).
                                                 t
               Important Terms and Concepts
               Beta random variable    Exponential random      Mean-function of a continuous   Standard deviation-continuous
               Chi-squared distribution   variable                random variable         random variable
               Continuity correction   Gamma function          Normal approximation to   Standardizing
               Continuous uniform      Gamma random variable      binomial and Poisson   Standard normal random
                  distribution         Gaussian distribution      probabilities           variable
               Continuous random variable  Lack of memory property-  Normal random variable  Variance-continuous random
               Continuous uniform random   continuous random   Poisson process            variable
                  variable                variable             Probability density function  Weibull random variable
               Cumulative distribution   Lognormal random variable  Probability distribution-
                  function             Mean-continuous random     continuous random
               Erlang random variable     variable                variable
   171   172   173   174   175   176   177   178   179   180   181