Page 75 - Arrow Pushing in Inorganic Chemistry A Logical Approach to the Chemistry of the Main Group Elements
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2.3 REDUCTIVE COUPLINGS  55
               The metal presumably donates a single electron to the ketone to form a ketyl radical:

                                     Me      Me         Me      Me
                                          C                 C
                                                                                  (2.13)
                                          O                 O
                                    Mg
                                                                Mg
               Two ketyl radicals then couple to form a magnesium dialkoxide:

                                                    Me  Me               Me     Me
                  Me      Me Me     Me         Me            Me       Me          Me
                       C                           C      C                C   C
                                 C
                       O                           O      O               O     O
                           Mg    O                    Mg                     Mg
                                                                                  (2.14)
               On aqueous work-up, the dialkoxide forms the expected 1,2-diol; the specific one shown
               below is called pinacol, after which this reaction is named:
                       Me     Me
                    Me          Me                         Me     Me
                         C   C                           Me          Me    2+
                                                             C   C     +  Mg      (2.15)
                        O     O       +
                                     O                    HO       OH
                           Mg    H
                                  H      H

                  Yet a third example (there are many!) of reductive coupling is the acyloin condensation,
               which involves the coupling of two esters:

                                         O
                                                        O       OH
                                                1. Na
                                    2                                             (2.16)
                                     R      OR       +
                                                2. H 3 O  R     R

               The first step is similar to that of pinacol coupling:
                                                                 −
                                        O                      O
                                                       +                          (2.17)
                                  Na                  Na  +
                                    R      OR               R      OR

                                                                               −
               The radicals then couple, and the coupling product eliminates alkoxide ions (RO ) to yield
               a diketone, as shown below:
                       −          −             −        −
                      O           O             O        O      −     O       O
                                                             − 2 OR
                                                                                  (2.18)
                   R      OR RO      R         R          R
                                                RO      OR            R       R
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