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Variational methods and adaptive grid generation  165

                        will help readers to write their own programs to generate grids for different geometries
                        to match particular requirements.)



                        6.4.1 The L-functional and the Winslow model

                        We begin with the observation that according to eqns (6.9), (6.10), and (6.12), the
                        Euler-Lagrange equations for the functional
                                            1        2      2      2      2
                                        I =      {(x ξ ) + (x η ) + (y ξ ) + (y η ) } dξ dη,  (6.38)
                                            2  R

                        where R is the computational domain 0   ξ   1, 0   η   1, are the pair of Laplace’s
                        equations
                                                       2
                                                             2
                                                      ∂ x   ∂ x
                                                         +      = 0
                                                      ∂ξ 2  ∂η 2
                                                             2
                                                       2
                                                      ∂ y   ∂ y
                                                         +      = 0.                       (6.39)
                                                      ∂ξ 2  ∂η 2
                          This is the differential model presented in eqns (5.5). So we see that the associated
                        transformation minimizes the functional I, which by eqns (1.158) may be written as
                                                    1
                                                I =       (g 11 + g 22 ) dξ dη.            (6.40)
                                                    2   R
                          In view of the remarks above on the properties of g 11 and g 22 , we call this the
                        L(length)-functional. Equations (6.39) are to be solved subject to boundary conditions
                        such that x and y are specified on the four (b,t,l,r) boundaries of the physical domain.
                        Thus
                                              x(ξ, 0) = x b (ξ);  x(ξ, 1) = x t (ξ)
                                              x(0,η) = x l (η);  x(1,η) = x r (η)
                                              y(ξ, 0) = y b (ξ);  y(ξ, 1) = y t (ξ)
                                              y(0,η) = y l (η);  y(1,η) = y r (η).
                          As mentioned in Section 5.1, this transformation can generate satisfactory grids,
                        but the Jacobian is not guaranteed to be non-zero, and folding of the grid can occur,
                        particularly when the physical domain is not convex.
                          If, by contrast, we formulate the variational problem
                                              2        2        2        2
                                 1        ∂ξ       ∂ξ      ∂η       ∂η
                              δ                +        +        +         dx dy  = 0,     (6.41)
                                 2   R    ∂x       ∂y      ∂x       ∂y
                        where the integration is taken over the physical domain R andweseekthe transforma-
                        tion ξ = ξ(x, y), η = η(x, y) which minimizes the integral, then the Euler-Lagrange
                        equations must be the pair of Laplace’s equations
                                                             2
                                                       2
                                                      ∂ ξ   ∂ ξ
                                                         +      = 0
                                                      ∂x 2  ∂y 2
                                                             2
                                                       2
                                                      ∂ η   ∂ η
                                                         +      = 0,                       (6.42)
                                                      ∂x 2  ∂y 2
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