Page 129 - Boiler_Operators_Handbook,_Second_Edition
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114                                                                               Boiler Operator’s Handbook

               some efficiencies listed at other firing rates in your  losses from 100 to get percent efficiency. Surprisingly
               boiler documentation you’ll notice that those others are  it is easier and far more accurate to determine some of
               labeled “predicted performance” and only the full load  the heat losses as a percent of the input so determining
               is guaranteed. The problem with that wisdom is the  efficiency using the heat loss method is the most widely
               boiler seldom, if ever, operates at full load. Whenever  accepted method.
               you have input, suggest that any new boiler you pur-     The Power Test Code (PTC-4.1) provides a struc-
               chase be guaranteed for performance at a load you will  tured basis for calculating boiler efficiency by two meth-
               have, say 50% or 75%. That doesn’t violate the ABMA’s  ods, input-output and heat loss. All the larger boilers
               rule. Today some chiller manufacturers, and possibly by  we installed while I worked for Power and Combustion
               the time this book is printed some boiler manufactur-  were tested using both methods in a modified form of
               ers may, guarantee the part load operating efficiency of  the Power Test Code. The cost of performing those tests
               their equipment.                                     in strict accordance with the Code could not be justified
                    Occasionally you will see a boiler efficiency guar-  for even the larger boilers (up to 200,000 pounds per
               anteed at something around 50% to 75% load. That is  hour of steam) that we installed. The primary modifica-
               probably a sales tactic because the maximum operating  tions we made to the Test Code included shorter test
               efficiency of a boiler is typically in that range. As the  runs (three hours instead of the required eight to twelve)
               load and firing rate decreases the volume of flue gas  and less frequent measurements (every twenty minutes
               decreases. The heating surface, on the other hand, stays  instead of every ten) so we could get two test runs in
               the same. Therefore the flue gas spends more time in  within one day and with only one man collecting data.
               contact with a proportionally larger heating surface so  Of course in those days we used an actual Orsat ana-
               more heat is transferred.                            lyzer which took some time to operate, not one of those
                    You should notice that when you create your own  nice electronic analyzers we have today.
               performance documentation because the stack tempera-     An examination of the results of the hundreds of
               ture will drop as you reduce firing rate from full load.  test runs we made revealed a typical deviation in the
               Somewhere lower the efficiency will start to drop off   input-output efficiency of as much as five percent while
               because the flue gas is channeling so only a small por-  the heat loss results were normally within one percent.
               tion of it is contacting the heating surface. As the firing  That’s why I can say, with a reasonable degree of confi-
               rate decreases it becomes more difficult for the fuel and  dence, that the heat loss method is very acceptable.
               air to mix completely so excess air must be increased to     I always get a kick out of some organizations indi-
               prevent CO and efficiency suffers further. The radiation  cating that they conducted hundreds of boiler efficiency
               losses also become more significant as the load decreas-  tests. During my twenty years at PCI we only ran about
               es. All these factors influence the operating efficiency of  two  hundred  boiler  efficiency  tests  using  that  modi-
               the boiler to different extents at different loads.  fied approach to the Test Code. Each test did consist of
                    Heat loss efficiency is determined by backing into  several test runs so I can say we made hundreds of test
               the value. An efficiency is considered to be the output  runs. Those were formal tests that included a printed
               (what you get out of it) divided by the input (what you  report with all the calculations, records of collected data,
               put into it) with the result of the division multiplied by  and fuel analysis. They were not boiler tests conducted
               100.                                                 in strict accordance with the Test Code but they were a
                         Efficiency = Output ÷ Input × 100          lot closer than what some people call a boiler efficiency
                                                                    test.
                    The loss, and in the case of a boiler it’s a loss of     I don’t consider a strip of narrow paper with a list
               heat, is the difference between the input and output.  of analysis values, temperatures, and a calculated boiler
               Therefore, the output is equal to the input less the heat  efficiency representative of a boiler test. Some firms that
               losses. By substituting input less losses for the output in  claim they’ve done hundreds of tests haven’t included
               the formula we get a formula that doesn’t include out-  one fuel analysis. Unless you have the fuel analysis the
               put at all.                                          test is simply flawed because the hydrogen to carbon
                                                                    ratio of fuels varies considerably. The modern flue gas
                     Efficiency = (Input – losses) ÷ Input × 100    analyzer contains programmed calculations based on an
                                                                    assumed fuel analysis and the odds that your fuel and
                    If we can calculate the losses as a percent of the  the values used by that program are identical are slim to
               input then all we have to do is subtract the percent  none. The results are only representative and based on
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