Page 286 - Calculus Demystified
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Chapter 1












                                         (c)                                (d)                  273
















                                        (e)                                (f)

                                                          √
                       12.    (a)  sin(8π/3) = sin(2π/3) =  3/2
                                                          √          √
                              (b)  tan(−5π/6) =[−1/2]/[− 3/2]= 1/ 3
                                                             √
                              (c)  sec(7π/4) = 1/ cos(7π/4) =  2
                                                                              √         √
                              (d)  csc(13π/4) = csc(5π/4) = 1/ sin(5π/4) = 1/[− 2/2]=− 2
                              (e)  cot(−15π/4) = cot(−7π/4) = cot(π/4) = cos(π/4)/ sin(π/4) =
                                   √       √
                                   [ 2/2]/[ 2/2]= 1
                                                  √
                              (f)  cos(−3π/4) =− 2/2
                       13. We check the first six identities.
                                                          √
                                                                                         2
                                                                             2
                                                                   2
                              (a)  cos π/3 = 1/2, sin π/3 =  3/2, cos π/3 + sin π/3 =[1/2] +
                                   √
                                         2
                                   [ 3/2] = 1/4 + 3/4 = 1.
                                                         √                        √
                              (b)  cos π/3 = 1/2, sin π/3 =  3/2, −1 ≤ 1/2 ≤ 1, −1 ≤  3/2 ≤ 1.
                                            √                             √
                                                                              2
                                                              2
                              (c)  tan π/3 =  3, sec π/3 = 2, tan π/3 + 1 =[ 3] + 1 = 3 + 1 =
                                    2
                                          2
                                   2 = sec π/3.
                                              √               √                   √
                                                                                      2
                                                                    2
                              (d)  cot π/3 = 1/ 3, csc π/3 = 2/ 3, cot π/3+1 =[1/ 3] +1 =
                                           √
                                                      2
                                               2
                                   4/3 =[2/ 3] = csc π/3.
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