Page 287 - Calculus Demystified

Solutions to Exercises
274
(e) sin(π/3 + (−π/6)) = sin(π/6) = 1/2, sin π/3 cos(−π/6) +
√ √
cos π/3 sin(−π/6) =[ 3/2][ 3/2]+[1/2][−1/2]= 1/2.
√
(f) cos(π/3 + (−π/6)) = cos(π/6) = 3/2, cos π/3 cos(−π/6) −
√ √ √
sin π/3 sin(−π/6) =[1/2][ 3/2]−[ 3/2][−1/2]= 3/2.
14. We shall do (a), (c), (e).

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Fig. S1.14(a)

Fig. S1.14(c)

Fig. S1.14(e)

15. (a) θ = (15/2) ◦
(b) θ =−60 ◦
(c) θ = 405 ◦
(d) θ = (405/4) ◦
(e) θ = (540/π) ◦
(f) θ = (−900/π) ◦
16. (a) θ = 13π/36 radians
(b) θ = π/18 radians
(c) θ =−5π/12 radians