Page 194 - Calculus Workbook For Dummies
P. 194

178       Part IV: Integration and Infinite Series





                Q.   Consider f t ^ h, shown in the following       A 5 ^ h adds a bit to  A 4 ^ h — roughly a
                                                                      f
                                                                                      f
                     figure. Given the area function                trapezoid with “height” of 1 and “bases” 2
                             x                                      and 3 (along the dotted lines at x = 4 and
                     A x = # ^h  f t dt, approximate  A 4 ^ h,      x = 5) that thus has an area of 2.5, so  A 5 ^ h
                      f ^
                                h
                                                 f
                                                                                                      f
                            2                                       is roughly 6 plus 2.5, or 8.5.
                     A 5 ^ h,  A 2 ^ h, and  A 0 ^ h. Is  A f increasing
                      f
                            f
                                      f
                     or decreasing between x =  5 and x =  6?       A 2 ^ h is the area between 2 and 2, which is
                     Between x =  8 and x =  9?                       f
                                                                    zero.
                        y
                            x = 2  x = 4  x = 5                     A 0 ^ h is another area roughly in the shape of
                                                                      f
                                                                    a trapezoid. Its height is 2 and its bases are 2
                      5
                                                                    and 3, so its area is 5. But because you go
                      4
                                                                    backwards from 2 to zero, A 0 ^ h equals –5.
                                                                                            f
                      3
                                                                    Between x = 5 and x = 6,  A f is increasing. Be
                      2
                                                     f (t)
                                                                    careful here: f t ^ h is decreasing between 5
                      1
                                                                    and 6, but as you go from 5 to 6,  A f sweeps
                                                         x          out more and more area so it’s increasing.
                           1  2  3  4  5  6  7  8  9  10
                                                                    Between x = 8 and x = 9, while f t ^ h is
                                                                    increasing  A f is decreasing. Area below the
                A.   A 4h is the area under f t ^ h between 2       x-axis counts as negative area, so in moving
                      f ^
                     and 4. That’s roughly a rectangle with a       from 8 to 9,  A f sweeps out more and more
                     base of 2 and a height of 3, so the area       negative area, thus growing more and more
                     is about 6. (See the shaded area in the        negative, and thus  A f is decreasing.
                     figure.)
               1.   For problems 1 through 4, use the area     2.   Where (from x =  0 to x =  8) does  A g reach
                                     x
                    function  A x = # ^h  g t dt and the follow-    a. its maximum value?
                              g^
                                         h
                                    / 1 2
                    ing figure. Most answers will be approxima-     b. its minimum value?
                    tions. Where (from 0 to 8) does  A g equal 0?
                                                                Solve It
                    y
                      x =  1            x = 6
                        2
                   5
                   4
                   3
                   2                             g (t)
                   1
                                                         x
                        1  2   3  4   5  6   7  8


                Solve It
   189   190   191   192   193   194   195   196   197   198   199