Page 90 - Chemical equilibria Volume 4
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66     Chemical Equilibria
                           NOTE  3.6.– it must be carefully noted that relation [3.35] applies only to
                           mixtures of  gases,  and is not demonstrated for reactions in a  condensed
                           solution.
                           3.1.7. Influence of the choice  of reference pressure on the
                           equilibrium constant

                             The equilibrium  constant of partial pressures does not depend on the
                           pressure in the experiment, but instead depends on the reference pressure.
                           However, we may be led to change the reference pressure, which leads to an
                           alteration of the value of  K r () P  . This occurs, in particular, when we
                           use tables of old thermodynamic data (before 1980), for which the
                           reference pressure was that of the  standard state chosen theoretically
                                                      5
                                                                                     5
                           at 1 atmosphere (i.e. 1.129×10 Pa) instead of 1 bar (exactly 10 Pa), as is
                           used today.
                             If we know the general expression of  the Gibbs energy function with
                           pressure, we can write:

                                       P
                                 ∂  ln K r ()  =  1 ∂ Δ g  0  = −  Δ v 0 0               [3.36]
                                                         r
                                                 r
                                   ∂ P 0  RT ∂  P 0     RT
                             However, for perfect gases, we have:

                                    0
                                 Δ v =  RT ∑ ν i                                         [3.37]
                                  r0
                                       P 0  i
                             Hence the variations of the constant with the reference pressure:


                                      P
                                 ∂ ln K  ()  ∑ ν i
                                      r  =−  i                                           [3.38]
                                   ∂ P 0     P 0
                                                             0
                                                                    0
                             Between two reference pressures  P  and  P , by integration we find:
                                                            (1)     (2)
                                   ( )       ∑  k ν
                                    0
                                    2 P
                                          0
                                 K r (2)  ⎛  P (1)  k ⎞
                                   ( )  = ⎜  ⎜  P 0  ⎟  ⎟                                [3.39]
                                    0
                                    2 P
                                 K r (1)  ⎝  (2) ⎠
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