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308                                                      Chapter 6

            Table 6.17 Filter-Cake Specific-Resistance Parameters  (Source Ref. 27).


                                                10
                          Substance        a 0(10 )m/kg a  Exponent, n
                   Asbestos                     —
                   Calcium carbonate                          0.19
                   Celite                       —             0.14
                   Crushed limestone            —              ——
                   Gairome clay                 282           0.60
                   Ignition plug clay           —             0.56
                   Kaolin                       —              —
                   Kaolin, Hong Kong pink       101           0.33
                   Solkofloc                   0.0024         1.01
                   Talc                         8.66          0.51
                   Titanium dioxide             32            0.32
                   Zinc sulfide                 14            0.69
                                                8
                   General range            Ixl0 tolxl0 3    0 to  1.2

                 a)  To convert to ft/lb multiply bv  1.488.


            where P = P -  P is equal to the pressure drop across the cake at any point.  The
                  s   0
            exponent,  n,  usually varies  from  0.2  to 0.8. If n =  0,  the  cake  is  incompressible.
            Values of the specific resistance and n are given in Table 6.17.
                 After  substituting  Equation 6.20, 6.21, and dP s = -  dP into  Equation  6.19,
            and after  separating variables, we obtain,


            dP s  a 0  u v s dm
                                                                        (6.22)
            PS"     A F

            The  limits of integration for Equation 6.22 are:  at Xi = 0, PS = 0, m = 0 and at x =
            x 2, PS = P 0 -  Pi, and m = iris, where P, is the pressure at the interface  of the cake
            and  the  filter  medium,  as  shown  in Figure  6.11. Thus,  after  integrating  Equation
            6.22  across the cake, we obtain

                   0
            (Po-Pi) " 0
                                                                        (6.23)










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