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310                                                     Chapters

                The  equations  for  sizing  rotary-drum  filters  are  summarized  in  Table  6.18.
            Equation  6.18.1 is the liquid mass balance. In this procedure, y is a mass fraction.
            Because  the  cake  is  wet,  the  liquid  entering  the  filter  will  be  less  then  the  liquid
            leaving. Equation 6.18.2  is the solids mass balance, assuming that all the  solids in
            the  slurry  are  removed.  Solve  Equation  6.18.2  for  the  cake  formation  rate,  me.
            Then,  solve Equation 6.18.1  for the  filtrate  volumetric  flow  rate, V 2. Next, calcu-
            late  the  filtration  area  from  Equation  6.18.5  and  the  drum  area  from  Equation
            7.18.6.  Finally,  select  a  standard  rotary  filter  from  Table  6.20.  The  calculation
            procedure  for sizing  a rotary  filter  is  outlined  in  Table  6.19.  Example  6.5  illus-
            trates the sizing procedure.
                Operating  data  for  filtering  slurries  could  also  be  used  to  estimate  rotary-
            filter  areas.  Some  filtration  rates  are  given by Walas  [6].  Thus, by  dividing  the
            feed  rate of solids onto the  filter by the  filtration  rate, expressed as  kg of  solids/h
             2
            m , the filter  area can be estimated.
            Table  6.18  Summary of Equations for Sizing Rotary-Drum Filters____

            First Subscript: Entering Stream =1  —  Leaving Stream = 2
            Second Subscript: Liquid =1  —  Solids = 2 — c = wet cake
            Mass Balance
                  v
            Yu Pi i'= Ye/me + p z 'V 2                                (6.18.1)
            Yi/Pi V^yc^mc                                             (6.18.2)

            yu+yi, 2 ' = l                                            (6.18.3)
            y c/ + yc,2=i                                             (6.18.4)


            Rate Equation
                                2
                 (l-n')an'c u V F
              2 2
            A F  =  ———————————                                        (6.18.5)
                 2 V '  -  P v')
                     (P 0
                f                                                     (6.18.6)
            A F = 'A T
            System Properties
            Pi=yuPu' + yu'Pu'                                         (6.18.7)

            c 1 ,2=yi, 2 'pi                                          (6.18.8)
            a = ao'0V -  Pv')°                                        (6.18.9)
            Variables
            yi.i -  yc,2  - m s - pi - V 2 -  c,, 2  - a  - A F - A T




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