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328                                                     Chapter 6

           height  and  diameter  of  the  stripper.  First,  calculate  the  air  rate.  This  calculation
           requires calculating the minimum air rate, which is determined by the intersection
            of the  operating line  and the  equilibrium curve  as  shown in Figure 6.16. Because
            the  concentration  of methylene  chloride  is low, Henry's  law applies.  Shukla  and
            Hicks  [68]  have  compiled  Henry 's-law-constant  relationships  for many  organic
            compounds  found  in  wastewater.  For  methylene  chloride,  Henry's  law  constant,
            H, is given by

            log H (mm Hg) = 9.58 -  1 139/(t °C + 231) = 5.342

                       5
           H = 2.200  xlO  mm Hg
                              5
           y = (H/P) x = (2.2 x 10 / 760) x = 289.5 x
            Thus,  the  equilibrium  value  K k  =  289.5.  This  calculation  satisfies  Equation
            6.21.  11T or Equation  6.21. 8P.  We have  yet to  determine  if the  column  will con-
            tain trays or packing.
                Convert the mass fraction  of methylene  chloride  in the  entering  wastewater
            stream to mole fraction.

                    4
            x lk = IxlO"  (18 / 84.94) = 2.119xlO~ 5
                From Equation 6.21.2S, the exit water concentration,

                                5
            *2k = (1-0.99) 2.1 19xlO~  = 2.1 19xlO~ 7
                Next, convert the wastewater flow rate from gal/day to Ibmol/h.
                   6
                Ixl0 gal  1  day  1  ft 3  62.00 Ib  1  Ibmol

                 1  day  24  h  7.481  gal  1  ft 3  18  Ib
                       4
            m L = 1.919xl0  Ibmol/h (8.707 xlO 4  kgmol/h)
                From Equation 6.21. IS, the minimum air flow rate,

                          5
                 2.119xlO~ -  2.119xlO~ 7
                                             4
           m vm = —————————————       1.919xl0  = 65.59 Ibmol/h (29.7  kgmol/h)
                                5
                 289.5 (2.1 19x10  ~ )-0
                According to Equation 6.21.3S, the actual air flow rate,






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