Page 354 - Chemical process engineering design and economics
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Separator Design 333
Minimum Number of Stages
log (X LK / XHK)D (XHK/ X LK)B
N M = ———————————————— (6.27.2)
log (a LK)av g
Minimum Reflux
(Cti)avg X iF
I _ q — 2^ j —— (p.z I ,j)
- 0
a
x
( i)avg iD
RM + 1 = Z i —————— — where (a LK)av g > 6 > (ocmOavg (6.27.4)
- 9
Optimum Reflux Ratio
Ro (1.6 -YO)
—— = ————— (Xo - 7.5) + 1.6 (6.27.5)
R M 6.5
Y 0 = ————————————— (6.27.6)
1.0614 (a LK)av g- 0.4175
0 55 ( LK)av8
X 0 = log (X LK/X HK)D (XHK/X LK)B (xLK/x^p ' " (6.27.7)
Number of Equilibrium Stages
Y e =l-Xe Be (6.27.8)
Y e = (N e -N M )/(N e +l) (6.27.9)
T7
1 (\\
_
"V"
/"T>
\*^Q
y^e — \K>Q ~ D K-M \ ) / ' /T? 4- 1 "\ *) I' fi (D.ZI.L\J)
B e = 0.105 log Xe +0.44 (6.27.11)
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