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The Laplace Transform of Common Functions of Time


         Thus, we have the transform pair


                                             G t –  a œ  e – as                                (4.54)


         for V !  . 0
         Example 4.6

                   – at
         Find L e ^  u t   `
                       0
         Solution:

                                                    f             f
                                                                           –
                                       – at           – at – st         s +  a t
                                  L e ^  u t   `  =  ³  e  e  dt =  ³  e  dt
                                          0
                                                   0             0
                                                                  f
                                                                       1
                                                                  –
                                                      1 ·
                                                =  §  – ----------- e     s +  a t  =  -----------
                                                  ©  s + a ¹          s + a
                                                                  0
         Thus, we have the transform pair
                                             – at        1
                                            e   u t   œ  -----------                           (4.55)
                                                 0
                                                       s +
                                                           a
         for V !  –  . a
         Example 4.7


                 ­  n – at  ½
         Find L t e    u t   ¾  0
                 ®
                 ¯          ¿
         Solution:

         For this example, we will use the transform pair of (4.52), i.e.,

                                              n         n!
                                             t u t   œ  -----------                            (4.56)
                                                0
                                                       s n +  1
         and the frequency shifting property of (4.14), that is,


                                           e – at ft   œ  Fs + a                               (4.57)

         Then, replacing   with s +  a  in (4.56), we get the transform pair
                        s







        Circuit Analysis II with MATLAB Applications                                            4-19
        Orchard Publications
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