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A Variational Inequality Theory Chapter | 4 89


                                   n
                           Let v ∈ R be fixed. We have
                                         1
                                         ( I + M)u i + q,u i − v −  (v) +  (u i ) ≤ 0.
                                         i
                           Taking the limit inferior as i →+∞ and using the lower semicontinuity of  ,
                           we obtain
                                             Mu + q,u − v −  (v) +  (u) ≤ 0.          (4.47)

                                                                   n
                                                                                         n
                           Since the vector v has been chosen arbitrarily in R , (4.47) holds for all v ∈ R .
                           The existence result follows.
                              From Theorem 4 and Proposition 20 we have

                                                   PD0 n ∪ P0 n ⊂ Q0 n ,

                           and thus if

                                                  (M, ) ∈ PD0 n ∪ P0 n
                           and
                                                     B(M, ) ={0},
                           then

                                                     (M, ) ∈ Q n .
                           This, together with Proposition 16, gives the following:

                           Corollary 6. If
                                                  (M, ) ∈ PD0 n ∪ P0 n
                           and

                                            D( ) ∞ ∩ N 0 (M) ∩ K(M, ) ={0},
                           then
                                                              n
                                                   R(M, ) = R .
                           Example 46. Let
                                                      ⎛           ⎞
                                                          1  0 0
                                                      ⎜           ⎟
                                                  M = ⎝ −210 ⎠
                                                          0  0 1
                           and
                                                   3
                                             (∀x ∈ R ) :  (x) =   R×R×R + (x).
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