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Customer Survey Design, Administration, and Analysis  81

            Example 4.5
            In a customer satisfaction survey, the preliminary results indicate that the pro-
            portion of unsatisfied customers is very close to the proportion of satisfied
            customers, and the population size is N = 2500. What sample size is needed if
            we want the accuracy of the survey to be within ±3 percent of the true pro-
            portion, with 95% confidence?
            Using Eq. (4.5)

                                                  ×
                                             2
                                                 .
                                           .
                       p − )]1
                                                     .
                    Z  2  [(  p N         1 96 ×  ( 0 5 0 5 2500)
                                                      )(
             n =     a /2          =                           =  749
                                               ×
                                                        ×
                                         2
                 2
                    p − )] (1
                                                 .
                                             .
                                       .
                                                           .
                Z a /2 [(  p +  N − )1 ∆ 2 p  1 96 × ( 0 5 0 5) +  2499 ( 0 03)  2
            This sample size is smaller than that of Example 4.4.
        Determination of Sample Size for Interval-Scale Variables
        In survey analysis, some variables are interval-scale variables. For example,
        personal income, age, and evaluation scores based on the Likert scale are all
        interval-scale variables. The population means of these interval-scale variables
        m are usually of interest. The sample mean of the interval-scale variable  x  is
        often used as the statistical estimate of population mean m. Similarly, we would
        like m as close to m as possible. From the properties of the normal distribution,
        and if the random sampling method is used, the probability distribution of  x  is
                                     ⎛   s ⎞
                                          2
                                 x ~  N m ,  ⎟                  (4.6)
                                     ⎜
                                     ⎝   n ⎠
        The 100(1 − a)% confidence interval for µ is
                                     s
                             x ±  Z     =  x ± ∆
                                  a/2         m                 (4.7)
                                      n
        where ∆ is the margin of error for µ.
               m
        By using the relationship
                                          s
                                 ∆ = Z a/2                      (4.8)
                                  m
                                           n
        we can derive the sample size rule:
                                      Z s  2
                                       2
                                  n =  a                        (4.9)
                                       ∆ 2 m
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